Velocity as a Vector: Plane Ground Velocity Calculation

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SUMMARY

The discussion focuses on calculating the ground velocity of a light plane traveling at 175 km/h on a heading of N8°E, while encountering a 40 km/h wind from N80°E. The correct ground velocity is determined to be 167 km/h at a direction of N5°W. The solution involves breaking down the velocities into north-south (NS) and east-west (EW) components, utilizing trigonometric functions to resolve the vectors accurately.

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Homework Statement



A light plane is traveling at 175km/h on a heading of N8°E in a 40km/h wind from N80°E. Determine the plane's ground velocity.

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The Attempt at a Solution



After I did all the graphing and trig. I came out with x^2 = 175^2 + 40^2 - 2(175)(40)cos108

which ends up being roughly 191.18, but the answer tells me its 167 km/h, N5°W

If anyone could help me out with this it would really be great, I am having a rough time with it.

Thanks for your time.
 
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Break it up into components: NS, EW. The direction NS is y = 175 sin(82) - 40 sin(10), where + is N. The direction EW is x = 175cos(82)-40cos(10), where + is E. To get their length, calculate D = \sqrt{x^2+y^2}. I'll leave the direction to you.
 
Thanks a bunch! that helped tons!
 

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