Velocity of an Object in Uniform Circular Motion

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SUMMARY

The discussion focuses on calculating the velocity of an object in uniform circular motion with a mass of 0.5 kg, a radius of 2 meters, and a centripetal force of 4 N. The correct approach involves using the equation F = mv²/R to derive the velocity. The participant initially misapplied algebra and struggled with significant figures, leading to an incorrect answer. The correct calculation yields a velocity of 4 m/s, aligning with one of the provided answer choices.

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  • Understanding of uniform circular motion principles
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  • Knowledge of algebraic manipulation
  • Basic concepts of significant figures in calculations
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Argella
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Homework Statement


An object of mass 0.5 kg is swung in uniform circular motion. The radius is 2 meters, and the force exerted is 4 N. Calculate the magnitude of the velocity.

Answer Choices:
a) 0.25 m/s
b) 1 m/s
c) 4 m/s
d) 16 m/s

Homework Equations


v = 2piR/T
F = mv^2/R

The Attempt at a Solution


Since I didn't know the variable time, I couldn't use the velocity equation. Next, I tried plugging in the variables for the centripetal force equation and solving for velocity:

4 = (0.5)v^2/2
4 = 0.5/2 + v^2/2
4 = 0.3 + v^2/2 <- 0.3 because of significant figures
(subtracted 0.3 from both sides)
4 = v^2/2 <- 4 because of significant figures
(multiplied both sides by 2)
8 = v ^2
(took the square root of both sides)
v = 3 which isn't one of my answer choices.

Maybe I'm not doing my algebra correctly or maybe I'm not using the right equation, but I couldn't find another equation using the variables I have. If I knew the time it took for one revolution I could use the velocity equation, but I don't know how to find time and I couldn't find an equation for finding it.
 
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Argella said:
4 = (0.5)v^2/2
4 = 0.5/2 + v^2/2
There is an algebra mistake in going from the first to the second step. You have essentially turned a product into a sum instead.

On a side note, when taking significant figures into account, do so only on the final answer. If you keep rounding off at each step, you will find that the rounding-off error grows substantially larger after each step, and the final answer you obtain might be significantly off the correct one.
 
Ohh, okay, that makes a lot more sense. I'll be sure to keep that in mind about significant figures in the future, too.

Thanks a lot!
 

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