Velocity of atomic (hydrogen) electrons

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SUMMARY

The velocity of atomic hydrogen electrons is calculated to be approximately 242,000 m/s, which is significantly less than the speed of light (c). This velocity can be derived using the equation mv² = 27 eV, where m represents the mass of the electron and v is its velocity. To find the ratio of the electron's velocity to the speed of light, the equation v/c = √(27/500,000) is utilized. Understanding these calculations is essential for grasping the behavior of electrons in atomic structures.

PREREQUISITES
  • Basic understanding of quantum mechanics
  • Familiarity with the concept of electron velocity
  • Knowledge of kinetic energy and momentum equations
  • Understanding of electron mass and energy units (eV)
NEXT STEPS
  • Study the principles of quantum mechanics related to atomic structure
  • Learn about the relationship between kinetic energy and velocity in quantum systems
  • Explore the concept of electron momentum in atomic physics
  • Investigate the implications of relativistic speeds in particle physics
USEFUL FOR

Students of physics, researchers in quantum mechanics, and anyone interested in the fundamental properties of atomic electrons will benefit from this discussion.

nuby
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Hello,

I've been wondering about the velocity of hydrogen electrons. I've read that 242,000 m/s was the correct velocity, however, I thought electrons would travel at c. How does one calculate this number?

Thanks in advance.
 
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Why would/should electrons travel at c?

One can measure/calculate the mean momentum & kinetic energy of the atomic electron, then it is trival to obtain its velocity.
 
mv^2=27 eV, so v/c=\sqrt{27/500,000}
 
Can you explain that equation, if you get a chance? Why does mv^2=27ev
Thanks.
 

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