What is the Conservation of Energy Principle in Bungee Jumping?

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Homework Help Overview

The discussion revolves around the application of the conservation of energy principle in the context of a bungee jumping scenario. Participants are analyzing the energy transformations involved as a jumper falls from a platform and interacts with a bungee cord.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to apply the conservation of energy equation, considering kinetic energy, gravitational potential energy, and elastic potential energy. There are questions regarding the correct values for height and stretch of the bungee cord at a specific point in the jump.

Discussion Status

Some participants have provided guidance on the correct interpretation of height and the stretch of the bungee cord. There is an ongoing exploration of the values to be used in calculations, with some participants clarifying the relationship between the jumper's height above the water and the corresponding stretch of the bungee cord.

Contextual Notes

Participants are working under the constraints of the problem statement, which includes specific values for mass, height, and spring constant. There is an acknowledgment of potential errors in substitution and calculation, as well as the need to accurately determine the stretch of the bungee cord at different heights.

jasonbans
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Homework Statement


A bungee jumper of mass 64.5 kg (including safety gear) is
standing on a platform 48.0 m above a river. The length of
the unstretched bungee cord is 10.1 m. The force constant
of the cord is 65.5 N/m. The jumper falls from rest and just
touches the water at a speed of zero. The cord acts like an
ideal spring. Use conservation of energy to determine the
jumper’s speed at a height of 12.5 m above the water on
the first fall.

Homework Equations


Ek=1/2mv^2
Ep=mgh
Ee=1/2kx^2

The Attempt at a Solution


so i did mgh = 1/2mv^2 + 1/2kx^2 and solve for v but somehow i am not getting the answer 6.3m/s
 
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jasonbans said:

Homework Statement


A bungee jumper of mass 64.5 kg (including safety gear) is
standing on a platform 48.0 m above a river. The length of
the unstretched bungee cord is 10.1 m. The force constant
of the cord is 65.5 N/m. The jumper falls from rest and just
touches the water at a speed of zero. The cord acts like an
ideal spring. Use conservation of energy to determine the
jumper’s speed at a height of 12.5 m above the water on
the first fall.

Homework Equations


Ek=1/2mv^2
Ep=mgh
Ee=1/2kx^2

The Attempt at a Solution


so i did mgh = 1/2mv^2 + 1/2kx^2 and solve for v but somehow i am not getting the answer 6.3m/s

You may have substituted in some incorrect values, or you may have "mis-used" you calculator.

Show us your substitution / simplifications so we can see what went wrong.
 
this is what i did
 

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jasonbans said:
this is what i did

Two problems:

When 12.5 m above the water, the jumper has not descended 48m, so you h value is not appropriate, and the bungee has not been stretched 12.5 m, so your x value is not appropriate.
 
12.5 above the water meaning 48 subtract 12.5 = 35.5m for the height?
i don't know how much it stretched by am i suppose to calculate it?
 
thx got the answer now
 
Last edited:
jasonbans said:
is the height 35.5 m and it stretched 25.5m right?

if it was 10.0 m long to start with it will have stretched 25.5m

edie: the h value is 35.5, yes. best called the change in height.
 

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