Velocity of Comet at a given distance

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SUMMARY

The discussion centers on calculating the speed of Halley’s Comet when it crosses the orbit of Neptune, approximately 5 billion kilometers from the sun. The initial speed at its closest approach is 54.6 km/s, and the conservation of energy principle is applied to determine the speed at a greater distance. The user encountered discrepancies in their calculations, obtaining 8.3 km/s instead of the expected 0.8 km/s. Participants confirmed that conservation of energy should yield the correct result, indicating potential errors in the user's calculations.

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Homework Statement


Halley’s Comet travels in a highly eccentric (non-circular) orbit. At its closest approach, it is about 9×10^7 km away from the sun and travels with a speed of 54.6 km/s. What is the comet’s speed when it crosses the orbit of Neptune, about 5 billion kilometres from the sun?

Homework Equations



Conservation of Energy, Ei = Ef

The Attempt at a Solution



I have made numerous attempts utilised conservation of energy because I don't see why we would need to bring angular momentum into it (given that we're not told that 5 billion km is the apopasis and therefore can't reduce it to mvr), why does my conservation of energy equation give me an answer of 8.3 km/s when the answer should be 0.8 km/s? Any help would be much appreciated. Whenever I insert the provided answer into the conversation of energy formula, it just doesn't work out.
 
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Hamish Taylor said:
I have made numerous attempts utilised conservation of energy because I don't see why we would need to bring angular momentum into it (given that we're not told that 5 billion km is the apopasis and therefore can't reduce it to mvr), why does my conservation of energy equation give me an answer of 8.3 km/s when the answer should be 0.8 km/s? Any help would be much appreciated. Whenever I insert the provided answer into the conversation of energy formula, it just doesn't work out.
We might be better able to find errors in your work if you were to show your work. Set angular momentum to one side and show us one attempt at a conservation of energy approach.
 
Hamish Taylor said:

Homework Statement


Halley’s Comet travels in a highly eccentric (non-circular) orbit. At its closest approach, it is about 9×10^7 km away from the sun and travels with a speed of 54.6 km/s. What is the comet’s speed when it crosses the orbit of Neptune, about 5 billion kilometres from the sun?

Homework Equations



Conservation of Energy, Ei = Ef

The Attempt at a Solution



I have made numerous attempts utilised conservation of energy because I don't see why we would need to bring angular momentum into it (given that we're not told that 5 billion km is the apopasis and therefore can't reduce it to mvr), why does my conservation of energy equation give me an answer of 8.3 km/s when the answer should be 0.8 km/s? Any help would be much appreciated. Whenever I insert the provided answer into the conversation of energy formula, it just doesn't work out.

You are right, conservation of energy should work. I got nearly the same result as you.
 
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