Velocity problem determining x and y components

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To determine the x and y components of the initial velocity for an object in parabolic motion, the horizontal distance traveled (100 m) and the launch angle (30°) are key factors. The equations of motion can be expressed as x = v_x * t and y = -4.9t^2 + v_y * t, where v_x and v_y are the horizontal and vertical components of velocity, respectively. The relationship between the components can be established using the tangent of the launch angle, leading to the equation v_y/v_x = tan(30°). By solving these equations simultaneously, one can find the values for the time of flight, v_x, and v_y. The process emphasizes the connection between horizontal and vertical motion in projectile dynamics.
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An object undergoing parabolic motion travels 100 m in the horizontal direction before returning to its initial height. If the object is thrown initially at a 30° angle, determine the x component and the y component of the initial velocity. (Neglect any effects due to air resistance.)

I am not sure how to go about solving... I got an initial vector from the throw but I don't think it can be the initial velocity vector since I have no judgment of time.. could someone show me the process of solving this?
 
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If we let "v_x" and "v_y" be the components of velocity in the x and y directions, respectively, then x= v_xt and y= -4.9t^2+ v_yt so we have y= -4.9t^2+ v_yt= 0 (the projectile hits the ground) and x= v_xt= 100 (the projectile hits the groud after 100 m). The fact that "the object is thrown initially at a 30° angle" means that v_y/v_x= tan(30). That gives you three equations to solve for the three values, t, v_x, and v_y.
 
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brandon133 said:
An object undergoing parabolic motion travels 100 m in the horizontal direction before returning to its initial height. If the object is thrown initially at a 30° angle, determine the x component and the y component of the initial velocity. (Neglect any effects due to air resistance.)

I am not sure how to go about solving... I got an initial vector from the throw but I don't think it can be the initial velocity vector since I have no judgment of time.. could someone show me the process of solving this?

The time taken for the object to travel horizontally 10m is equal to the time taken from launching up and back to same level.

It is a single body, at same place(different x and y coordinates) and at same time.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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