- #1

brandon133

- 1

- 0

I am not sure how to go about solving... I got an initial vector from the throw but I dont think it can be the initial velocity vector since I have no judgment of time.. could someone show me the process of solving this?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter brandon133
- Start date

- #1

brandon133

- 1

- 0

I am not sure how to go about solving... I got an initial vector from the throw but I dont think it can be the initial velocity vector since I have no judgment of time.. could someone show me the process of solving this?

- #2

HallsofIvy

Science Advisor

Homework Helper

- 43,021

- 970

- #3

rl.bhat

Homework Helper

- 4,433

- 9

If vcosθ is the x component of the velocity, what is the expression for the range x?

- #4

azizlwl

- 1,065

- 10

An object undergoing parabolic motion travels 100 m in the horizontal direction before returning to its initial height. If the object is thrown initially at a 30° angle, determine the x component and the y component of the initial velocity. (Neglect any effects due to air resistance.)

I am not sure how to go about solving... I got an initial vector from the throw but I dont think it can be the initial velocity vector sinceI have no judgment of time.. could someone show me the process of solving this?

The time taken for the object to travel horizontally 10m

It is a single body, at same place(different x and y coordinates) and at same time.

Share:

- Replies
- 4

- Views
- 2K

- Last Post

- Replies
- 15

- Views
- 3K

- Last Post

- Replies
- 2

- Views
- 4K

- Last Post

- Replies
- 3

- Views
- 13K

- Replies
- 25

- Views
- 2K

- Last Post

- Replies
- 7

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 1K

- Replies
- 6

- Views
- 1K

- Last Post

- Replies
- 16

- Views
- 12K

- Last Post

- Replies
- 2

- Views
- 10K