"In a chase scene, a movie stuntman is supposed to run right off the flat roof of one city building and land on another roof 1.6 m lower."
"If the gap between the buildings is 4.5 m wide, how fast must he run? "
Vf^2 = V0^2 + 2a (Xf-X0)
This might not be the right equation, but it's the one I've been trying to use
The Attempt at a Solution
Vf^2 = 2(9.8)(4.776)
4.776 is the hypotenuse of the 1.6m and 4.5m distances