Verification of a problem -> force needed for car stopping in 1.8cm

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SUMMARY

The discussion centers on calculating the force required for a car to stop within 1.8 cm, highlighting the importance of using the correct initial velocity. Participants clarified that the initial velocity should be converted from 37 km/h to 10.28 m/s for accurate calculations. Additionally, they identified practical limitations affecting braking, including tire friction, excessive negative acceleration, and heat generation in brake components. The conversation emphasizes the necessity of precise data interpretation and the implications of braking physics in real-world scenarios.

PREREQUISITES
  • Understanding of basic physics concepts, particularly kinematics.
  • Familiarity with unit conversions, specifically between kilometers per hour and meters per second.
  • Knowledge of static friction coefficients, particularly rubber-asphalt interactions.
  • Awareness of the effects of negative acceleration on passenger safety.
NEXT STEPS
  • Calculate braking force using the formula F = ma, where 'm' is mass and 'a' is deceleration.
  • Research the impact of static friction coefficients on vehicle stopping distances.
  • Explore the physics of g-forces experienced during rapid deceleration.
  • Investigate the thermal dynamics of brake systems under extreme conditions.
USEFUL FOR

Automotive engineers, physics students, and anyone interested in vehicle dynamics and safety measures during braking.

simphys
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Homework Statement
picture
Relevant Equations
newton's 2nd law of motion F_net = ma
Kinematic equation: v_fx^2 = v_0x^2 + 2*a_x*(deltaX)
1644778250216.png

hello guys can someone verify my solution (in the picture) whether the solution is correct or I guess the steps followed would be enough. There is no solution in the book for this one but wanted to be sure.

Thanks in advance
 

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You used 37 m/s for the initial velocity of the car when it is given as 37 km/h. The method is correct.
 
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Why does your homework statement talk of a 850 kg car traveling at 45 km/h when the question you copy says a 840 kg car traveling at 37 km/h?
Note v0 = 37 km/h, NOT 37 m/s!
First rule of any test is READ THE QUESTION ACCURATELY.

Edit; kuruman got there first!
 
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kuruman said:
You used 37 m/s for the initial velocity of the car when it is given as 37 km/h. The method is correct.
mjc123 said:
Why does your homework statement talk of a 850 kg car traveling at 45 km/h when the question you copy says a 840 kg car traveling at 37 km/h?
Note v0 = 37 km/h, NOT 37 m/s!
First rule of any test is READ THE QUESTION ACCURATELY.

Edit; kuruman got there first!
Thanks guys, appreciate it! And well no.. I mistakenly copied the wrong question. I typed it in google but found a question on cheg from the same book (other edition) with just the numbers changed hence why, my apologies
 
Then, you have three practical limitations to that strong braking effect:
1) Friction between tires and asphalt.
2) Excessive negative acceleration (g-force) for passengers.
3) Excessive heat in brake pads-discs.
 
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Lnewqban: That's why you need to supply your own brick wall (or borrow a neighbor's). The car *can* stop on a dime, though.
 
I don't see why advertise a car that can stop on a dime. Its air bags would have to be deployed every time it did so. If it doesn't have air bags for that reason, its driver can stop on a dime exactly once in a lifetime.
 
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Lnewqban said:
Then, you have three practical limitations to that strong braking effect:
1) Friction between tires and asphalt.
2) Excessive negative acceleration (g-force) for passengers.
3) Excessive heat in brake pads-discs.
Thanks for the indication that.
Mike S. said:
Lnewqban: That's why you need to supply your own brick wall (or borrow a neighbor's). The car *can* stop on a dime, though.
I presume that that was sarcastic😄
 
simphys said:
Thanks for the indication that.
Velocity used in the calculation should be 10.28 m/s.

After you calculate the force necessary to stop in 1.8 cm, just for curiosity, you could see how much force the maximum available static friction (rubber-asphalt μ is around 0.8) would actually allow, as well as how big of g-force the passengers would experience.
 
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kuruman said:
its driver can stop on a dime exactly once in a lifetime.
While this may be true for the spirit of the idiom, if taken literally the driver can do it many many times. Stopping on a dime would technically just require you to be on top of it as you come to a rest. 😏
 
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  • #11
Lnewqban said:
Velocity used in the calculation should be 10.28 m/s.

After you calculate the force necessary to stop in 1.8 cm, just for curiosity, you could see how much force the maximum available static friction (rubber-asphalt μ is around 0.8) would actually allow, as well as how big of g-force the passengers would experience.
wow that's insane very curious how this these coefficients for the frictions are calculated (I guess looking at the molecular interaction between both surfaces explains that.. and lots of experimentation ofc)
 
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