Verifying coherence time formula with g(t) = e^(-|t|/t_c)

[Observer Two]

Homework Statement

I have the complex term $g(t) = e^{\frac{-|t|}{t_c}}$ which is the degree of the coherence.

Homework Equations

Now I want to verify that:

$t_c = \int_{-\infty}^\infty \! |g(t)|^2 \, dt$

The Attempt at a Solution

$\int_{-\infty}^\infty \! |g(t)|^2 \, dt = \int_{-\infty}^\infty \! |e^{\frac{-|t|}{t_c}}|^2 \, dt = \int_{-\infty}^\infty \! e^{\frac{-|t|}{t_c}} e^{\frac{|t|}{t_c}} \, dt = \int_{-\infty}^\infty \! 1 \, dt$

2 Problems now.

First: The integral doesn't have a value if I integrate from - infinity to infinity.
Second: The value of the indefinite integral is t. Not t_c.

What am I missing here?

 

[NasuSama]

You didn't multiply $e^{-\frac{|t|}{t_c}}$ by itself. Instead, the second multiplier misses the negative sign. Check your work carefully and try again evaluating the integral.

 

[Observer Two]

Huh? I'm really missing something here.

$|z|^2 = z z^*$

So if in my case $z = e^{\frac{-|t|}{t_c}}$ then

$z^* = e^{\frac{|t|}{t_c}}$

Or not?