Vertical Circle Motion: Acceleration at Top vs. Bottom

[ethex]

Homework Statement

A ball of mass m is suspended from a rope of length R. The ball is set into freely swinging circular motion a vertical plane. The centripetal acceleration of the ball at the top of the circle is 13g. What is the centripetal acceleration of the ball at the bottom of the circle.

Homework Equations

The Attempt at a Solution

At the top,

T + mg = mv^2/R


At the bottom, T - mg = mv^2/R

My question is does Ttop and Tbtm the same?

Hint for this question?

 

[grzz]

Using conservation of energy principle helps you get v(top) in terms of v(bottom) and you may deduce whether the tensions are equal.

 

[ethex]

Ui + Ki = Uf + Kf

0 + 0.5mVbtm^2 = 2mgR + 0.5mVtop^2

Right?

 

[grzz]

Yes. Continue.

 

[ethex]

I got 17g!

 

[grzz]

Now you know what the answer to your question.

 

[ethex]

Yes! thank you.!