A vertical jump or vertical leap is the act of jumping upwards into the air. It can be an exercise for building both endurance and strength, and is also a standard test for measuring athletic performance. It may also be referred to as a Sargent jump, named for Dudley Allen Sargent.
So far I believe that speed changes during vertical circular motion, and its very hard to get uniform circular motion that is in the vertical plane.
This is because there is a difference in vertical height between the bottom/top of the circle so at the top the object must have done work against...
Writing from Cuba.
This is canoeing:
There are multiple causes for it but the one I'm interested in is when it is caused by directional air flow (AKA wind).
If a breeze is blowing across my stogie from the same direction for an extended duration, one side will burn down much more than the...
I wanna be checking homogeneity of space(only interested in vertical) for simplicity and example we can do is "ball is dropped". To check homogeneity, we use either passive or active transformation and I'm interested in lagrangians.
I heard that we can write lagrangians such as: ##L =...
For the horizontal case of SHM, we only need to consider KE and EPE. But should we also take GPE into consideration when we are dealing with a vertical case?
a) I can find the compressive strain on the aluminium column using the formula ##\sigma = E\epsilon## as we know ##\sigma = F/A##. The area of the column is ##A = \pi r^2 = 0.126m^2## and the force on the column is ##F = 300*(9.8)N = 2940N##. The stress therefore is ##\sigma =...
Hi there,
I hope that somebody can help me with this.. Any response is much appreciated!
Let's have a vertical closed-loop system where the fluid circulates using the pump. The temperature in both sections gradually changes (the upcomer section is heated up) so that the densities, velocities...
I got the answer right, but it involved some guessing. So I’m here to make sure I got a conceptual understanding of this.
Normal force is a contact force. If the car was not in contact with the loop (or barely in contact), the loop would exert no normal force on the car. So at the minimum...
For part (c) of this problem,
My working is
However, the tricky part is to find theta. I tried to draw the situation so that I could find theta:
It appears that theta = 90 degrees. However, this does not seem to be correct. Does anybody please know how to correctly find theta in terms of...
This was how the solution was arrived in the text,
Net torque = F block x d block x sin ϴ0 + F rod x d rod x sin ϴ0 - T R sin 90
0 = 2mg x 2R x sin ϴ0 + m x R x sinϴ0 - T R
T = 5 mg sinϴ0
I'm wondering do we have to resolve the forces for rod and block in to...
Question is simple, as we all know water boils at the bottom surface and it forms tiny bubbles. These bubbles grow up and rise in the water until they detach. What is the acceleration of these bubbles compared to gravitational acceleration?
- Is it constant velocity?
- Is it approximately...
I am trying to solve this and get the equations of motion using the Lagrangian method.
I could do all the steps but the equations (especially the third one) seems..weird.
What am I doing wrong? Sorry if the equations aren't in their simplest form, they are pulled straight from Wolfram...
Applying rotational equilibrium at the center pivot we get:
+mg(R) + Mg(Rcos60°)–2Mg(R) = 0.Using cos60° = ½ we arrive at the answer 3M/2
I don't understand why cosine is used instead of sine in the above equation. I see the y component mg is acting perpendicular to the x component and so from...
From the equation for centripetal force, I can see that the centripetal force is proportional to v^2. Does this have something to do with why there is a normal force at the top? Does the velocity of the object require there to be a normal force? If so, why is that the case?
Summary: A 5.0- cm -diameter cylinder floats in water. How much work must be done to push the cylinder 11 cm deeper into the water?
F =Aρgx
A 5.0- cm -diameter cylinder floats in water. How much work must be done to push the cylinder 11 cm deeper into the water?
F =Aρgx
x being the...
I have created a table which has some equations in it. The LaTeX code is as follows:
\documentclass[a4paper,12pt]{article}
\usepackage{mathtools}
\usepackage{physics}
\usepackage{tabularx}
\usepackage{makecell}
\newcommand{\tev}{\ensuremath{\mathcal{U}}}...
A golf is launched at a speed v,f and launch angle, β,f. The slope of the green is equal to φ. At some point the ball is located on the rim of a hole. The side view (a) and overhead view (b) looks as in the attached image.According to the author of the [paper][2] "The Physics of Putting" the...
Hi all,
I have some data from an automatic weather station, with recordings of both 2m air temperature and 2m air pressure and also the surface temperature. Is it possible to estimate vertical wind speeds between the AWS and the surface based upon this data? Imagine T_a = 15 degrees and T_s =...
In an I-beam, the shear flow is usually shown drawn as on the left, not as drawn on the right. I do not understand why. I do understand:
The total horizontal shear force must be zero, consistent with statics.This is satisfied in both images.
The vertical direction matches the direction of the...
Diagram
Problem
If the mass of the block is too large and the block is too close to the left end of the bar (near string B) then the horizontal bar may become unstable (i.e., the bar may no longer remain horizontal).
What is the smallest possible value of x such that the bar remains stable...
This is the problem I am working on at the moment. The question states that the bar is at rest in this state. At a 60 degree angle to the horizontal and supported by the vertical spring at B.
Small oscillations are introduced and I am required to find the equation of motion and the natural...
#F= m\frac{v^2}{r} = mw^{2}r#
#m=5#
#r=0.9#
#F= 5\frac{v^2}{0.9} = (0.9)5w^{2}#
#5\frac{v^2}{0.9} = (0.9)5w^{2}#
#\frac{v^2}{0.9} = (0.9)w^{2}#
#v=0.9w#
then I get stuck cause I have both unknowns in one equations (i bet it has something to do with the question’s use of “minimum” but I...
This is the problem,
Let ##y=f(x)= (x-2)^2##. The graph of ##y=af(x)##can be obtained from the graph of ##y=f(x)## by a stretch parallel to the y- axis with scale factor ##a##. In our case here, ##a=3##, therefore the corresponding graph is as indicated in blue. Find my graph below using desmos.
Question:
A string spring is connected between two bodys with a rope above them.
M1 = 25Kg
M2 = 50KG
Distance between them is 100m.
I answered a bit and got to the point where the distance between the two masses are 110m ( the mass below got 10m lower and is on balance, I mean, acceleration = 0...
Suppose we have a vertical circular motion with gravity according to the image below.
In the leftmost and rightmost positions the resultant force is pointing diagonally down. Isn't the resultant force supposed to be pointing at the center at all times in a circular motion? What am I getting...
I know how it’s done. So let’s jump on the question. The displacement that came was negative 6 cm. I want to know how this formula describes perfectly negative displacements.
I don’t understand the mechanism. If I assume ##ut## to be distance traveled in absence of g then what is ##-1/2gt^2##...
A rocket of initial mass m0 is launched vertically upwards from the rest. The rocket burns fuel at the constant rate m', in such a way, that, after t seconds, the mass of the rocket is m0-m't. With a constant buoyancy T, the acceleration becomes equal to a=T/(m0-m't) -g. The atmospheric...
When we apply a force to throw a body upward why doesn’t it accelerate in upward direction. I think the answer is continuous force of gravity slowing it down. So it is de accelerating from the moment it’s released. But recently we have applied a force so it should accelerate ?
It says when the ball is shot the can is released and they both hit each other at the same height ie they travel same distance down. But that is only possible when the ball starts it’s downward journey the same time as the can starts it’s own. Shooting a ball upward direction will give it some...
I just have a question that could you guys make an equation that expresses the terminal velocity based on followed condition?
- When diameter increase, velocity decrease
- velocity should change depending on both cylinder and sphere's diameter
- We know every variable
- The sphere is in...
So I am trying to understand how to estimate the amount of deflection [D] the vertical beam shown above would experience if the base it is attached to is accelerating at a constant acceleration [a] of 9.81 m/s.
I assume the Force [F] would be equal to weight of the vertical beam (mass x...
(A) and (B) are obviously wrong but I think both (C) and (D) are correct.
At the top, the forces acting on the mass are tension and weight, both directed downwards so the equation of motion will be:
$$\text{Tension}+\text{Weight}=m.a$$
$$\text{Tension}=m.a-\text{Weight}$$
Based on that...
I can evaluate the first beads motion easily A to B is -2Rj considering the point B as y=0 the motion of the bead will be -gt^2/2+2R=0 which implies t=2√(R/G) , this is ok but what I am struggling with is A to C I can see that the angle between the beads weight and it's negative normal force...
Hi,
How do I left align the text below? Also, how do I create vertical spaces above and below the line stating "Subbing the following expressions..."? Could you please help me with it?To derive 14(ii) m_{0} \gamma^{2} \frac{d^{2} y}{d t^{2}}=e E_{y}^{\prime} from 13(ii) m_{0} \frac{d^{2}...
I apologize in advance for any errors in my concepts or assumptions. Feel free to correct me wherever I am wrong. Thanks in advance for the help.
There is a vertical shaft which will be operated at around 600 rpm (N) which can be achieved in 2 seconds (or even 4 just an assumption). The shaft...
I investigated the flow rate of differing dilutions of glycerol through an orifice of a vertical tube and obtained the following:
I'm looking for a way to quantify these results so looked to Poiseuille's Law;
I'm pretty sure my graph does not show inverse proportion? Could anyone advise me as...
Let's say a mass is gently laid on top of a massless spring. The spring compresses.
There is a change in the height of the mass. Therefore, there is a change in the gravitational potential energy: a decrease.
The compressed spring now has potential energy (it has gained energy).
The change...
I'm trying to figure out alternative ways to lift the roof on a pop-up camper that I'm refurbishing. There is limited space, and it needs to be lifted from beneath. I'm trying to avoid completely gutting it if possible which is what I'd have to do with a standard cable system. Any ideas?
It...
Say that I have a continouos beam resting on top of column spanning across 3 column. The applied load is UDL on the beam, here's how the BMD look like. My question is whether the connection between the beam and column need to sustain the moment ? Which point need to sustain the moment ? All 3...
Assuming zero spring mass and zero friction,
At the greatest value of x, the loss in gravitational potential energy should equal the loss in elastic potential energy.
so I did
(1/2)kx^2=mgx
to isolate x in the formula,
x=(2mg)/k
then I plugged in my values so:
(2*13.6*9.81)/8.8= 30.3218...
I know that the answer is 0 J (no NET work was done) because there is symmetry to the problem and this symmetry comes from the fact that the direction of force changes, BUT I don’t know why the force changes (I have an idea; TBD below in #4). When I did this problem I thought I could find the...
Hello:
I was looking for a widespread convention (akin to Hibbeler's, Beer's, etc) that deals with the sign convention of a vertical bar for bending moments.
For example, without knowing in advance, how do I draw the bending moment at a cut passing through point E in the figure attached?
Beam...
Hi,
I was given this problem saying that a ball is thrown vertically up in the air and returns to its initial position after 4 seconds. The acceleration due to gravity is given to be equal to 10m/s^2.
I tried to attempt this problem by using the equation :
v^2 - v0^2 = 2ah by considering...
I suppose the trick in this question is to realize that the drag acts in opposite directions when the ball ascends and descends and that the ball actually takes less time to rise and more time to fall than normally. I make a small sketch of the problem alongside.
Attempt : The total time of...
Hello to everyone :smile:
I'd like to study this problem.
You have a 2D guide, described by an equation y = y (x) in a reference interval x ∈ I = [a, b], placed in a cartesian vertical plane Oxy.
The guide is frictionless and the only force that is acting is the gravity force.
On this track, a...