Vibration: Transmissibility ratio sign change when damping is equal to zero

AI Thread Summary
The discussion centers on the transmissibility ratio equation, specifically the conditions under which to take the positive or negative square root when damping is zero. The transmissibility ratio (T.R.) is generally considered a positive value, but the negative root is applicable when the ratio r (the natural frequency to excitation frequency) is greater than one. Participants clarify that r indicates how close the driving frequency is to the resonant frequency and does not directly relate to damping. The conversation reflects some frustration with the topic, indicating a lack of interest in the class material. Understanding the conditions for the roots is essential for accurately applying the transmissibility ratio in vibration analysis.
Pipsqueakalchemist
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So for the transmissibility ratio equation, after doing a lot of questions when damping is zero and I have to take the square root of the denominator. Some questions take the positive root (1-r^2) while for other questions the solution takes the negative root (r^2-1). Can someone explain when we take the positive or negative root please and thank you
 

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The T.R. is a ratio of force magnitudes and is generally taken as a positive value. So the negative root is taken when r>1.
 
It looks like Pipsqueak is no longer with us... Nevertheless, r in the above equation is the ratio between natural frequency and excitation frequency (ω/ωn). It's a measure of how close the driving frequency is to the resonant frequency, and doesn't provide any explicit information on the damping.
 
onatirec said:
It looks like Pipsqueak is no longer with us... Nevertheless, r in the above equation is the ratio between natural frequency and excitation frequency (ω/ωn). It's a measure of how close the driving frequency is to the resonant frequency, and doesn't provide any explicit information on the damping.
Yea I stopped caring about that class so it’s whatever
 
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