Vinegar Concentration Calculation: % HC2H3O2 in a Diluted Solution

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To calculate the % HC2H3O2 in the diluted vinegar solution, first determine the molarity of acetic acid using the titration data with NaOH. The equation M1V1 = M2V2 can be applied, where M1 is the concentration of acetic acid in the diluted solution and V1 is the volume of the diluted sample. The density of vinegar is necessary for converting molarity to mass percent, and while not provided, it can be approximated based on typical vinegar density. Ultimately, the calculation requires knowledge of both the titration results and the density of the vinegar for accurate mass percentage determination.
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Homework Statement


After diluting 20.00mL of vinegar sample to 500.0 mL in a volumetric flask, a student titrated a 20.00 mL aliquot of this diluted solution against a 0.1120 M NaOH solution. The acetic acid requires 27.98 mL of base. What is the % HC2H3O2 in vinegar?

Homework Equations


M1V1 = M2V2

The Attempt at a Solution


I tried to find the concentration of vinegar when it is added to base. So M1(20.00mL) = (0.1120 M NaOH)(27.98 mL). But I have no idea how I am supposed to find the mass %. Do I have to apply the formula to get to the M before its dilution and then use the density of vinegar? (Even though the density is not mentioned in the problem?).
Thanks
 
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asadpasat said:
M1V1 = M2V2

You do know where this equation comes from (and when it will fail)?

http://www.titrations.info/titration-calculation

And yes, you should know the density of the initial solution. You may initially assume it is just that of a pure water (actually it is a bit higher, but not much).
 
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