Viscous Drag and Terminal Velocity

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SUMMARY

The discussion focuses on calculating the terminal velocity of deodorant spray droplets with a mass of 4x10^-12 kg and a radius of 0.1 mm in air with a viscosity of 2x10^-5 N·s/m². Using Stoke's Law, the terminal velocity is estimated to be approximately 0.3 mm/s. The calculations involve the balance of forces including weight, viscous drag, and upthrust, with a correction noted regarding the density of the droplets. The density of the droplets was questioned, indicating a need for accurate data to ensure valid results.

PREREQUISITES
  • Understanding of Stoke's Law and its application in fluid dynamics
  • Basic knowledge of forces including weight, viscous drag, and upthrust
  • Familiarity with the concepts of mass, radius, and density in physics
  • Ability to perform calculations involving gravitational acceleration (g = 9.8 m/s²)
NEXT STEPS
  • Review Stoke's Law and its implications for small particle motion in fluids
  • Learn about the effects of viscosity on terminal velocity in different fluids
  • Investigate the relationship between mass, volume, and density for spherical objects
  • Explore advanced fluid dynamics concepts such as laminar and turbulent flow
USEFUL FOR

Students studying physics, particularly those focusing on fluid dynamics, as well as professionals in fields involving aerosol dynamics and spray technology.

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Homework Statement



Droplets in a deodorant spray have mass of about (4x10^-12) kg and a radius of about 0.1mm. Estimate the terminal velocity of the droplets in Air of Viscosity (2x10^-5)Nsm^-2.

Homework Equations


Stoke's Law, F = 6pi rvu
where r = radius, v = velocity and u = viscosity.

Upthrust of an object = vpg (v = volume, p = density, g = gravitational acceleration)

The Attempt at a Solution


Since at terminal velocity, it is obvious that W = F + U. (where W = weight, F = viscous drag, U = upthrust.)

So we have,
F = W-U
6pi (0.1x10^-3)(2x10^-5)(v) = (4x10^-12)(9.8) - (4/3)(pi)(0.1x10^-3)^3(1.24)(9.8)
**Based on the assumption that the droplet is a sphere and the density of air is 1.24kg/m^3

We have,
v = (approx) 0.3mms^-1.

Is this true?

(@ ehild : Oops. Forgot the negative sign)
 
Last edited:
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"Droplets in a deodorant spray have mass of (4x10^12) kg "

Is this serious?:smile:

ehild
 
Something is still wrong with the data. What is the density of the droplets if the mass is 4^*10^-12 and the radius is 0.1 mm? ehild
 

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