Voltage across a battery while discharging

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    Battery Voltage
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Discussion Overview

The discussion revolves around the observed voltage across a 9.7 volt battery pack while it is discharging. Participants explore the reasons for a significant voltage drop from 9.4V (not in use) to 5.8V (in use), questioning the behavior of batteries under load and the implications of internal resistance.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that batteries are not perfect emf sources and that internal resistance can cause voltage drops under load.
  • Another participant challenges the extent of the voltage drop due to internal resistance, suggesting that a drop of 3.6V is unacceptable given typical internal resistance values.
  • A formula is presented to describe how the voltage delivered to a load depends on both load resistance and internal resistance.
  • There is a clarification that the original question pertains to the voltage across the battery itself, not across a resistive load.
  • Concerns are raised about the battery's ability to handle high current withdrawal, suggesting that excessive current draw could lead to significant voltage loss.
  • A participant mentions the possibility of the battery being near the end of its charge or failing, referencing open circuit voltage characteristics.
  • Another participant introduces the concept that the voltage of an electrochemical cell is concentration dependent, implying that prolonged use can lead to a drop in voltage.

Areas of Agreement / Disagreement

Participants express differing views on the causes of the voltage drop, with some attributing it to internal resistance and others suggesting the battery's state of charge or health. There is no consensus on the exact reason for the observed voltage behavior.

Contextual Notes

Participants mention various factors that could influence battery performance, including internal resistance, load characteristics, and the state of charge, but do not resolve the implications of these factors on the observed voltage drop.

zorro
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What should be the voltage across a 9.7 volt battery pack when it is in use (discharging)?
I used a multimeter to check that and got the reading as 5.8 V. It reads 9.4V when not in use. From my knowledge, a battery is a constant source of e.m.f. But the above observation is weird.
What is the problem?
 
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The voltage drop due to internal resistance (it is of the order of milli ohms) should be very less. May be about 0.2V in my case. A drop of 3.6V is unacceptable.
 
The voltage delivered to a resistive load depends on the load resistance and internal resistance of the supply:

V=ER/(R+r)

R= load resistance
r= internal resistance
E= EMF
 
The question is about the voltage across the battery not across a resistive load.

EDIT: I got your point there. Is it not possible that the battery is unable to handle high current withdrawal?
 
Last edited:
i'm not really sure why it is, but i got annoyed enough with the question to try and find out what the open circuit characteristics might be at near zero charge. search google (and maybe check out images) for 'open circuit voltage residual capacity' and i think that you will see that, depending on the battery type, open circuit voltage can be pretty high in a battery that is more or less dead. so, possibilities may be that you have far exceeded the normal current capacity of your battery, the battery needs charging, or the battery is failing.
 
Abdul Quadeer said:
The question is about the voltage across the battery not across a resistive load.

EDIT: I got your point there. Is it not possible that the battery is unable to handle high current withdrawal?

The higher the current withdrawal the greater the voltage lost across the internal resistance of the battery.Don't forget that withdrawing too high a current can prove to be expensive and dangerous.
 
Last edited:
hi
you may find the answer at "http://answers.yahoo.com/question/index;_ylt=AuunKfjGksf89bitoh96qNT_xQt.;_ylv=3?qid=20071007013353AAIQvZZ"
the voltage of electrochemical cell ,as you know from nernst equation is concentration dependent and when it used for a long time it will consumed and the voltage will dropped.
 

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