Volume of a solid limited by two paraboloids

  • Thread starter aicort
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  • #1
aicort
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Volume of a solid limited by these two paraboloids z=[tex]2x^2{}[/tex]+[tex]y^2{}[/tex] and z=12-[tex]x^2{}[/tex]-[tex]2y^2{}[/tex]



hi can someone help me? I tried to solve this and my solution was [tex]\ 24[/tex][tex]\Pi[/tex] is it correct? can someone solve this step by step?
 
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Answers and Replies

  • #2
jav
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I am assuming you are in calculus. In this case you would find the intersection of these two functions, and integrate the difference of the two functions over the areas.
 
  • #3
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Volume of a solid limited by these two paraboloids z=[tex]2x^2{}[/tex]+[tex]y^2{}[/tex] and z=12-[tex]x^2{}[/tex]-[tex]2y^2{}[/tex]



hi can someone help me? I tried to solve this and my solution was [tex]\ 24[/tex][tex]\Pi[/tex] is it correct? can someone solve this step by step?

How did you get your result of 24 pi? Show us what you did and we'll help you with it.

BTW, you should have posted this in the Calculus & Beyond section, not the Precalculus Math section.
 
  • #4
aicort
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How did you get your result of 24 pi? Show us what you did and we'll help you with it.

BTW, you should have posted this in the Calculus & Beyond section, not the Precalculus Math section.

yeah i know... i realized too late :P i hope someone move this thread to that section
look this is what i did

http://img413.imageshack.us/img413/2806/volt.th.jpg [Broken]
 
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  • #5
jav
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Looks good to me
 
  • #6
aicort
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you say so? i'm glad then... i thought it was wrong
thanks you guys :)
 

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