Volume of a solid limited by two paraboloids

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Homework Help Overview

The discussion revolves around finding the volume of a solid defined by the intersection of two paraboloids, specifically z=2x^2+y^2 and z=12-x^2-2y^2. The original poster seeks assistance in verifying their calculated volume of 24π.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to find the intersection of the two functions and consider integrating the difference between them. There are requests for clarification on the original poster's calculation process.

Discussion Status

Some participants have provided feedback on the original poster's work, expressing that it looks good, while others are encouraging further elaboration on the steps taken to arrive at the solution. The discussion is ongoing with no explicit consensus reached.

Contextual Notes

There is a note regarding the appropriateness of the thread's placement in the forum, as it was suggested that it belongs in the Calculus & Beyond section rather than Precalculus Math.

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Volume of a solid limited by these two paraboloids z=[tex]2x^2{}[/tex]+[tex]y^2{}[/tex] and z=12-[tex]x^2{}[/tex]-[tex]2y^2{}[/tex]



hi can someone help me? I tried to solve this and my solution was [tex]\ 24[/tex][tex]\Pi[/tex] is it correct? can someone solve this step by step?
 
Last edited:
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I am assuming you are in calculus. In this case you would find the intersection of these two functions, and integrate the difference of the two functions over the areas.
 
aicort said:
Volume of a solid limited by these two paraboloids z=[tex]2x^2{}[/tex]+[tex]y^2{}[/tex] and z=12-[tex]x^2{}[/tex]-[tex]2y^2{}[/tex]



hi can someone help me? I tried to solve this and my solution was [tex]\ 24[/tex][tex]\Pi[/tex] is it correct? can someone solve this step by step?

How did you get your result of 24 pi? Show us what you did and we'll help you with it.

BTW, you should have posted this in the Calculus & Beyond section, not the Precalculus Math section.
 
Mark44 said:
How did you get your result of 24 pi? Show us what you did and we'll help you with it.

BTW, you should have posted this in the Calculus & Beyond section, not the Precalculus Math section.

yeah i know... i realized too late :P i hope someone move this thread to that section
look this is what i did

http://img413.imageshack.us/img413/2806/volt.th.jpg
 
Last edited by a moderator:
Looks good to me
 
you say so? I'm glad then... i thought it was wrong
thanks you guys :)
 

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