Volume of Cone with Inscribed Sphere

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SUMMARY

The volume of a cone circumscribed around a sphere with a radius of 5 units can be expressed in terms of the variable x, which represents the additional height beyond the sphere. Using the Pythagorean theorem, the radius (r) of the cone is calculated as sqrt((x + 5)^2 - 25). The height of the cone is determined to be 10 plus an additional variable related to x. The relationship between the cone's dimensions and the variable x is established through the similarity of triangles formed in the geometric configuration.

PREREQUISITES
  • Understanding of Pythagorean theorem
  • Basic knowledge of cone and sphere geometry
  • Familiarity with similarity of triangles
  • Ability to manipulate algebraic expressions
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  • Explore the derivation of the volume formula for cones
  • Study the properties of inscribed and circumscribed shapes
  • Learn about geometric relationships in similar triangles
  • Investigate applications of Pythagorean theorem in three-dimensional geometry
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Students studying geometry, mathematics educators, and anyone interested in understanding the relationship between cones and spheres in geometric contexts.

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Homework Statement



A cone is circumscribed around a sphere. The radius of the sphere is 5 units.
Write the volume of the cone in terms of x.
There is a diagram.. I will try to describe it:
It is a cross section of the object (sphere in cone). From the center of the circle to the bottom left vertice of the triangle is length 5 + x. (5 is the radius, x is the rest of the line).

Homework Equations


The Attempt at a Solution



So I can get r of the cone with Pythagoras = sqrt((x + 5)^2 - 25). The height would be 10 + something. I'm not sure how the missing part of the height relates to x.
 
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The problem is that there are an infinite number of such cones. First draw a triangle circumscribing a circle (the sphere inside the cone seen from the side). Choose and angle for the vertex at the top of the sphere. That angle cannot be 0 or 180 degrees but it can be any other between. And then there exist a cone, having that angle at the vertex, circumscribing the sphere.
 
So how can I write the volume in terms of x ?
 
forumspherecone.jpg


I certainly wouldn't have chosen x as the main variable in this problem, but never mind that. Look at the figure. All you need to find the volume of the cone is its radius and height. So in the figure you need to get r and y in terms of x. r is easy from the right triangle AOB. Then you can get w + v in terms of y and x from triangle ABD. Then use the similarity of triangles ABD and DCO to get y in terms of x.
 

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