Volume Rate of Change: Understanding Math

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SUMMARY

The discussion focuses on the volume rate of change in relation to the formula $$\frac{dV}{dt}$$. Participants confirm that the correct substitution for $$\frac{dr}{dt}$$ is $$3\,\frac{\text{in}}{\text{min}}$$, emphasizing that this value should not be treated as a simple length measurement. Additionally, it is established that the volume rate of change is proportional to the square of the radius $$r$$, indicating a quadratic relationship rather than an exponential one.

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  • Familiarity with the concept of volume in geometric shapes
  • Knowledge of proportional relationships in mathematics
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karush
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View attachment 1561

on b) I think this is the point they wanted us to get
hope answers are correct its an even problem # so no ans in bk.
 
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Re: volume rate of change

Your results for part a) are correct. :D

In your working, where you evaluate $$\frac{dV}{dt}$$ for the given values of $r$, you should have replaced $$\frac{dr}{dt}$$ with $$3\,\frac{\text{in}}{\text{min}}$$ instead of $$3\text{ in}$$. Also, I think what they are looking for in part b) is that $$\frac{dV}{dt}$$ is proportional to the square of $r$. Thus it changes quadratically, not exponentially.
 

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