MHB Volume Rate of Change: Understanding Math

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The discussion focuses on understanding the volume rate of change in a mathematical context. It confirms that the results for part a) are correct but highlights an error in evaluating $$\frac{dV}{dt}$$, where $$\frac{dr}{dt}$$ should be expressed as $$3\,\frac{\text{in}}{\text{min}}$$. Additionally, it clarifies that $$\frac{dV}{dt}$$ is proportional to the square of the radius $$r$$, indicating a quadratic change rather than an exponential one. This distinction is crucial for accurately solving the problem. Understanding these relationships is essential for mastering the concept of volume rate of change.
karush
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on b) I think this is the point they wanted us to get
hope answers are correct its an even problem # so no ans in bk.
 
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Re: volume rate of change

Your results for part a) are correct. :D

In your working, where you evaluate $$\frac{dV}{dt}$$ for the given values of $r$, you should have replaced $$\frac{dr}{dt}$$ with $$3\,\frac{\text{in}}{\text{min}}$$ instead of $$3\text{ in}$$. Also, I think what they are looking for in part b) is that $$\frac{dV}{dt}$$ is proportional to the square of $r$. Thus it changes quadratically, not exponentially.
 
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