Waterslide and Energy Conservation

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Homework Help Overview

The discussion revolves around a physics problem related to energy conservation in the context of a waterslide. Participants are analyzing the energy transformations and forces acting on a rider and sled as they move through different points on the slide.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to apply the conservation of energy principle to calculate speeds and forces at various points. Questions arise regarding the initial kinetic energy of the sled, the calculations for work done, and the normal force in part D.

Discussion Status

Some participants have provided feedback on the calculations for parts A-C, suggesting corrections and clarifications. There is ongoing exploration of part D, with varying interpretations of what is being asked and how to approach it.

Contextual Notes

Participants note the importance of significant figures in calculations and discuss the role of additional forces, such as the vertical force from water, which may affect the overall force calculations.

minimario
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Homework Statement


O935WaF.png


Homework Equations



Conservation of energy, F=ma

The Attempt at a Solution



(a) By the conservation of energy, we use points A and C as the initial and final, ## \frac{1}{2} m v^2 - \frac{1}{2} m 2.5^2= (m)(g)(9.76) \Rightarrow v = 14.1 m/s ##

(b) Since ## W_{nc} = \Delta KE - \Delta PE, W = -\frac{1}{2} \cdot 80 \cdot 13.8^2 = --7952 J ##

(c) F = W / d = 146 N

(d)

I do not know what to do for part (D). Can somebody check if parts A-C are correct and give maybe a start at part D?
 
Last edited:
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minimario said:

Homework Statement


O935WaF.png


Homework Equations



Conservation of energy, F=ma

The Attempt at a Solution



(a) By the conservation of energy, we use points A and C as the initial and final, ## \frac{1}{2} m v^2 = (m)(g)(9.76) \Rightarrow v = 13.8 m/s ##

(b) Since ## W_{nc} = \Delta KE - \Delta PE, W = -\frac{1}{2} \cdot 80 \cdot 13.8^2 = -7618 J ##

(c) F = W / d = 152 N

(d)

I do not know what to do for part (D). Can somebody check if parts A-C are correct and give maybe a start at part D?

Part a): I think you forgot about the rider/sled's initial kinetic energy. Recall that the rider/sled leaves point A after being pushed with a speed of 2.5 m/s.

Parts b) and c): Conceptually, they look correct to me, but you'll have to redo them since they rely on the answer from part a).

Part d): I think it's asking you to calculate the normal force.
 
I have fixed A-C. Is the answer to part D 771?
 
minimario said:
I have fixed A-C. Is the answer to part D 771?
I suppose it depends on how many significant figures you are using to represent g. But if you are using 9.8 m/s2 for g, then yes, I think that's right.

(if you're using 9.81 m/s2 for g, there may be a very minor rounding error)
 
By the way, for part c), the water also provides a vertical force that counteracts gravity. So there's the horizontal force that you calculated above, and also this vertical force.

I'm not sure if your textbook wants you to consider that too, but technically it is a part of the total force that the water exerts on the sled. So you might want to find the magnitude of the vector sum and use that as the answer for part c).
 

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