Wave amplitude/energy relationship problem the square of one is one?

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SUMMARY

The relationship between wave amplitude and energy is defined by the equation E ∝ A², indicating that energy is proportional to the square of the amplitude. The discussion highlights a specific example where an ocean wave with a 1-meter amplitude corresponds to an energy value of 100 J, while the same wave measured in feet (approximately 3 feet) yields an energy value of 100 J when adjusted for unit conversion. The constant k varies based on the units used, demonstrating that the proportionality remains consistent across different measurement systems. This confirms that the perceived discrepancy in energy values arises solely from the units of measurement.

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  • Knowledge of mathematical relationships involving squares
  • Basic grasp of the concept of proportionality in physics
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Wave amplitude/energy relationship problem...the square of one is one!?

Hi,

1. I am trying to understand the relationship of wave amplitude and wave energy, knowing that Energy is proportional to Amplitude squared. My problem is that the proportion seems to differ for the same wave based on the unit used to define it.

For example:

a) An ocean wave with an amplitude of 1 meter seems to have a proportional energy value of 1, or a 1:1 ratio.

b) The exact same wave measured in feet (approximately 3 feet) has an energy value of 9, a 1:3 ratio.

2. I am using the equation E [tex]\propto[/tex] A2

3. It seems to me that the only answer is that you can calculate the proportional difference between two or more waves using this formula.
 
Last edited:
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There isn't really a problem here. Energy is equal to some constants times amplitude squared. Say E = kA^2. The k has units. Its value is different if you use different units. For example for some wave you might have k = 100 J/m^2. So if the wave is 1 m high, you get
E = 100 J/m^2 * (1 m)^2 = 100 J.
In feet, you would convert k = 100 J/m^2 = 100 J/(3 ft)^2 = 11 J/ft^2
and E = 11 J/ft^2 * (3 ft)^2 = 100 J.
 


Thanks Delphi51! That was very helpful.
 

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