Wave Equation PDE: Help Solve Test Problem

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SUMMARY

The discussion focuses on solving the wave equation partial differential equation (PDE) given by {{u}_{tt}}={{u}_{xx}}+1+x for the domain 00. The initial conditions are specified as u(x,0)=\frac{1}{6}{{x}^{3}}-\frac{1}{2}{{x}^{2}}+\frac{1}{3} and {{u}_{t}}(x,0)=0. The solution approach involves decomposing the function u(x,t) into v(x,t) and a polynomial a(x) to simplify the boundary conditions and eliminate the non-homogeneous term 1+x. The method of separation of variables is recommended to handle the boundary conditions u_x(0,t)=0 and u(1,t)=0.

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Hi, I have a test tomorrow and I'd like you to guys help me please.

Solve the following:

$\begin{align*}
& {{u}_{tt}}={{u}_{xx}}+1+x,\text{ }0<x<1,\text{ }t>0. \\
& u(x,0)=\frac{1}{6}{{x}^{3}}-\frac{1}{2}{{x}^{2}}+\frac{1}{3},\text{ }{{u}_{t}}(x,0)=0,\text{ }0<x<1. \\
& {{u}_{x}}(0,t)=u(1,t)=0,\text{ }t>0.
\end{align*}$

I think it can be solved by using $u(x,t)=v(x,t)+a(x)$ and then applying D'Alembert later, does this work?
 
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Since you have boundary condition you'll want to use separation of variables. It you let

$u = v + ax^3 + bx^2 + cx + d$

you can pick $a,b,c$ and $d$ such that the BC's are the same and the term $1+x$ in the PDE can be eliminated
 

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