Wave funtion and normalisation constant

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SUMMARY

The discussion focuses on finding the normalization constant (A) for the wave function \(\psi(x,t) = A[3\sin(\frac{\pi x}{L}) + 2\sin(\frac{2\pi x}{L})]\). The normalization condition is established through the equation \(A^2\int_{0}^{L}[\psi(x,t)]^2dx = 1\). The user successfully computes the first integral, yielding \(A^2\cdot \frac{9}{2}L\), but encounters difficulties with the second integral involving the product of sine functions. The discussion emphasizes the need to apply trigonometric identities to simplify the integral.

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  • Knowledge of normalization conditions for quantum states
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Homework Statement


find the normalisation constant (A)



Homework Equations


wave functcion
[tex]\psi (x,t)= A[3sin(\frac{\pi x}{L})+2sin(\frac{2\pi x}{L}][/tex]


The Attempt at a Solution


[tex]A^2\int_{0}^{L}[\psi(x,t)]^2dx=1[/tex]
[tex]A^2\int_{0}^{L}[9sin^2(\frac{\pi x}{L})+12sin(\frac{\pi x}{L})sin(\frac{2\pi x}{L})+4sin^2(\frac{2\pi x}{L})}]dx[/tex]

Homework Statement



i try to solve each integral separately
I have started with the first one and i got

[tex]A^2\int_{0}^{L}[9sin^2(\frac{\pi x}{L})]dx= A^2\cdot \frac{9L}{ \pi}\int_{0}^{\pi}sin^2tdt=A^2\cdot \frac{9L}{\pi}[\frac{1}{2}t+\frac{sin(2t)}{4}]\right]_{0}^{\pi}=A^2\cdot \frac{9}{2}L[/tex]
is it correct so far?

from the last integral i got
[tex]A^2\frac{L}{\2\pi}\int_{0}^{2\pi}4sin^2(2t)dt=A^22L[/tex]

i don't have a good idea for solving the second intregral...
 
Last edited:
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use the fact that, 2 sin A sin B = - cos (A + B) + cos (A - B) ..
 

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