Wave, given wavespeed, wavelength, amplitude - find w.

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SUMMARY

The discussion focuses on determining the angular frequency (w) of a wave given its wavespeed, wavelength, and amplitude. The participants analyze the equation 0 = sin(kx - wt) at x = 0, leading to the conclusion that w can be derived from the frequency. The confusion arises from the assertion that sin(-wt) equals zero, which is only true at specific instances, not universally. Ultimately, the participants agree that calculating frequency is a more reliable method for finding w.

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  • Understanding of wave equations and trigonometric functions
  • Knowledge of angular frequency and its relation to wavespeed and wavelength
  • Familiarity with the concept of frequency in wave mechanics
  • Basic skills in solving trigonometric equations
NEXT STEPS
  • Research the relationship between wavespeed, wavelength, and frequency in wave mechanics
  • Learn how to derive angular frequency (w) from wave parameters
  • Study the properties of the sine function and its implications in wave equations
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Students and professionals in physics, particularly those studying wave mechanics, as well as educators seeking to clarify concepts related to wave behavior and frequency calculations.

JoeyBob
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Homework Statement
See attached
Relevant Equations
y(x, t) = Asin(kx-wt)
What I chose to do was analyze what happened at x=0. At x=0 I know sin of whatever will be 0.

So 0=sin(kx-wt) and since x=0, w=Arcsin(0)/t. But this doesn't make sense because the answer isn't 0, its 0.695.
 

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JoeyBob said:
At x=0 I know sin of whatever will be 0.
You do? Why?
 
haruspex said:
You do? Why?

Because 0=sin(-wt), so sin of whatever would be 0.

I suppose I could calculate frequency to find w, but idk why this method doesn't work too.
 
JoeyBob said:
Because 0=sin(-wt)
But that is what I am questioning. Why do you say 0=sin(-wt)? That will only be true at certain times.
 
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haruspex said:
But that is what I am questioning. Why do you say 0=sin(-wt)? That will only be true at certain times.
Makes sense, thanks.
 

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