1. The problem statement, all variables and given/known data The velocity of the transverse waves produced by an earthquake is 8.9km/s while that of the longitudinal waves is 5.1km/s. A seismograph records the arrival of the transverse waves 73s before that of the longitudinal waves. How far away was the earthquakes? 2. Relevant equations [Broken] displacement= (Initial Velocity)(Time) + (0.5)(a)(time squared)???? 3. The attempt at a solution Given Answer: 8.7x10^2 km=870km=870,000m I wish I showed you guys the 12/13 problems out of this worksheet that I did to show that I did try and am not trying to mooch.. I scoured the internet and found some similar links.. http://www.glenbrook.k12.il.us/gbssci/phys/p163/ec/u10ec.html [Broken] https://www.physicsforums.com/showthread.php?t=88686 http://www.hopperinstitute.com/phys_waves.html [Broken] My last link basically showed.. they multiplied the fastest velocity by 98s.. How did they get 98s..I don't know.. Can anyone get me started on this? == I've tried.. 3.8km (difference in velocity displacement)=73s*x x=52m/2 .. Then try and use displacement formula.. But I have no acceleration value, so meh..