The velocity of the transverse waves produced by an earthquake is 8.9km/s while that of the longitudinal waves is 5.1km/s. A seismograph records the arrival of the transverse waves 73s before that of the longitudinal waves. How far away was the earthquakes?
displacement= (Initial Velocity)(Time) + (0.5)(a)(time squared)?
The Attempt at a Solution
Given Answer: 8.7x10^2 km=870km=870,000m
I wish I showed you guys the 12/13 problems out of this worksheet that I did to show that I did try and am not trying to mooch..
I scoured the internet and found some similar links..
My last link basically showed.. they multiplied the fastest velocity by 98s.. How did they get 98s..I don't know..
Can anyone get me started on this?
3.8km (difference in velocity displacement)=73s*x
x=52m/2 .. Then try and use displacement formula.. But I have no acceleration value, so meh..
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