Weak nuclear Vs Strong nuclear

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SUMMARY

The discussion clarifies the distinction between weak and strong nuclear interactions in particle decay, specifically using the example of a K- meson decaying into three charged pi mesons. The decay is attributed to weak interaction due to the kaon's short lifetime of approximately 10^-8 seconds, contrasting with the much faster strong interactions that occur in about 10^-23 seconds. Additionally, the change in strangeness during the decay indicates weak interaction, as strong interactions conserve strangeness. The discussion emphasizes the importance of analyzing quark and lepton states and utilizing Feynman diagrams to determine the responsible force in particle interactions.

PREREQUISITES
  • Understanding of particle physics concepts, including mesons and quarks.
  • Familiarity with weak and strong nuclear forces.
  • Knowledge of strangeness and its conservation laws in particle interactions.
  • Basic skills in drawing and interpreting Feynman diagrams.
NEXT STEPS
  • Study the principles of weak nuclear interactions in particle physics.
  • Learn about strong nuclear interactions and their characteristics.
  • Explore the concept of strangeness and its role in particle decay.
  • Practice drawing Feynman diagrams for various particle interactions.
USEFUL FOR

Particle physicists, students of physics, and anyone interested in understanding the mechanisms of particle decay and the fundamental forces at play in the universe.

jpa
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How do you determine in a particle interaction which force is responsible?

For example

a K- meson is found to decay into three charged pi mesons what force is involved?

The answer here is a weak interaction but why?
 
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Two reasons. First, the kaon lifetime is about 10-8 sec, and strong interactions typically occur in 10-23 sec. Second, strangeness is changed in the kaon decay and the strong interaction conserves it.
 
So could we say that strangeness number is the key.
If its conserved then the interaction was via the strong nuclear else its weak nuclear!
 
The key in this case, but it cannot be generally stated that that is the case.

A safe way to figure this out is to see what quarks/leptons exist in initial and final state and then write down feynman diagrams describing the transition from one into the other. If it can occur via the strong interaction, it will, if not then the weak interaction has a chance.

If there is a quark(anti-quark) which exist in only the initial state OR only the final state without its corresponding anti-quark(quark) the weak interaction has to play a part.

Hope that helps.
 

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