Weighing a Salmon in an Elevator: What's the Apparent Weight?

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SUMMARY

The discussion revolves around calculating the apparent weight of a 5.0 kg salmon in different elevator scenarios. When the elevator is at rest, the apparent weight equals the gravitational force, calculated as W = mg, resulting in 49 N. When moving upward at an acceleration of 2.5 m/s², the apparent weight increases to 62.5 N due to the additional upward force. Conversely, when moving downward at 3.2 m/s², the apparent weight decreases to 37.6 N, as the tension force must counteract the reduced acceleration. The correct application of Newton's second law (F = ma) is essential for accurate calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of forces and weight calculations
  • Familiarity with the concept of apparent weight
  • Ability to perform calculations involving acceleration and mass
NEXT STEPS
  • Study Newton's second law of motion in detail
  • Learn about tension forces in different contexts
  • Explore the concept of apparent weight in varying acceleration scenarios
  • Practice problems involving forces in elevators and other accelerating systems
USEFUL FOR

Students taking introductory physics courses, educators teaching mechanics, and anyone interested in understanding forces in non-inertial reference frames.

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Homework Statement



A 5.0kg salmon is weighed by hanging it from a fish scale attached to the ceiling of an elevator. What is the apparent weight of the salmon if the elevator is (a) at rest, (b) moving upward at 2.5 m/s2, and (c) moving downward at 3.2 m/s2?

Homework Equations



Sum of F = 0
F(t) - W = 0
F(t) = W

Sum of F = Ma
F(t) - W = Ma (W=mg)

F(t)<W Sum of F = Ma
W- F(t) = Ma

The Attempt at a Solution



i have trouble thinking out of the box to get the problem started. this is my very first time ever taking physics and i have not had a math or science class in a year. can anyone help me get started?! I would appreciate any help! Thank you!
 
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Part 1, you are correct. Parts 2 & 3 you have to correct formula, use F=ma. Part 2 you should get the correct answer which should be greater than the static weight. I can't tell if part 3 is a trick question since I believe that would make your "tension force" in the other direction i.e. a compression force and a rope can't carry compression...
 
brain fart..on part 3 since the acceleration is less than gravity you would still need a tension force up.
 
thank you for the response!
 

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