The discussion focuses on calculating the power required to accelerate a 1000kg elevator cab upward. The participants derive the acceleration as 0.75 m/s² and calculate the work done using the formula w = (1400kg)(9.8 + 0.75 m/s²)(1.5m), resulting in 22155 J. For part b, the force is determined as F = (1400kg)(9.8 m/s²) = 13720 N, leading to a power output of P = Fv = (13720N)(1.5m/s) = 20580 Watts. The conversation emphasizes that power is not constant during acceleration due to increasing kinetic energy and displacement over time.
PREREQUISITESPhysics students, mechanical engineers, and anyone interested in the dynamics of elevator systems and energy calculations in mechanical contexts.
So what did you answer for a?Edel Crine said:Gosh, now I got it...!
I really appreciate for continuous help from all of you...
With my harsh English, this is the only thing that I can say, all of you are the awesome