Weighing a Salmon in an Elevator: What's the Apparent Weight?

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Homework Help Overview

The problem involves determining the apparent weight of a 5.0 kg salmon when weighed in an elevator under different conditions of motion: at rest, moving upward, and moving downward. The subject area pertains to dynamics and forces, particularly focusing on the concepts of weight and tension in varying acceleration scenarios.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law (F=ma) and the relationship between tension and weight in different scenarios. Some express confusion about the implications of acceleration on the tension force, particularly in the context of downward motion.

Discussion Status

There is an ongoing exploration of the problem, with some participants providing feedback on the original poster's attempts and suggesting corrections to the approach. Questions about the nature of forces involved in downward acceleration are being raised, indicating a productive dialogue.

Contextual Notes

The original poster mentions a lack of recent experience in math or science, which may be influencing their confidence in tackling the problem. This context suggests a need for foundational understanding in physics concepts related to forces and motion.

Snowflake9
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Homework Statement



A 5.0kg salmon is weighed by hanging it from a fish scale attached to the ceiling of an elevator. What is the apparent weight of the salmon if the elevator is (a) at rest, (b) moving upward at 2.5 m/s2, and (c) moving downward at 3.2 m/s2?

Homework Equations



Sum of F = 0
F(t) - W = 0
F(t) = W

Sum of F = Ma
F(t) - W = Ma (W=mg)

F(t)<W Sum of F = Ma
W- F(t) = Ma

The Attempt at a Solution



i have trouble thinking out of the box to get the problem started. this is my very first time ever taking physics and i have not had a math or science class in a year. can anyone help me get started?! I would appreciate any help! Thank you!
 
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Part 1, you are correct. Parts 2 & 3 you have to correct formula, use F=ma. Part 2 you should get the correct answer which should be greater than the static weight. I can't tell if part 3 is a trick question since I believe that would make your "tension force" in the other direction i.e. a compression force and a rope can't carry compression...
 
brain fart..on part 3 since the acceleration is less than gravity you would still need a tension force up.
 
thank you for the response!
 

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