What am I doing wrong with the AMU conversion?

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The discussion revolves around calculating the mass defect of cobalt-59 and converting it from kilograms to atomic mass units (AMU). The user successfully calculated the mass defect in kilograms as 8.999737e-28 Kg. They are struggling with the conversion to AMU, having obtained a value of 0.5419895815 AMU, which is not being accepted by Webassign. The correct conversion method involves dividing the mass in kilograms by the conversion factor of 1.6605e-27 Kg per AMU. Clarification on the calculation process and ensuring the correct input format for Webassign is needed for successful submission.
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Homework Statement


Determine the mass defect of the nucleus for cobalt 5927Co, which has an atomic mass of 58.933 198 u. Express your answer in AMU and Kg.

Homework Equations


How do I get the AMU? Or Atomic Mass Unit?

The Attempt at a Solution


Ok, so I solved the answer in Kg. The answer in Kg is 8.999737e-28 Kg (This answer is correct). And I need to provide the answer in Atomic Mass Units also. I know the conversion factor is 1 amu = 1.6605e-27 Kg. My answer is .5419895815, but Webassign is not accepting the answer. Please help.
 
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I don't have a calculator near to me at the moment but all you need to do is divide your answer by 1.6605e-27 to get the units in amu
 
The number i plugged into webassign is the Kg divided by the conversion factor...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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