What Angle Causes a Sphere to Begin Sliding?

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Homework Help Overview

The problem involves determining the angle at which a sphere begins to slide when a mass is placed on it, considering the coefficient of static friction. The context is within the subject area of dynamics and friction.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the angle using the inverse cosine function but questions the correctness of their approach. Other participants inquire about the normal force and frictional forces involved, suggesting a need to clarify the relationships between these forces and the angle.

Discussion Status

Some participants have provided guidance on the use of different trigonometric functions, leading to a potential resolution for the original poster. However, there is no explicit consensus on the methods being discussed, and multiple interpretations of the problem are evident.

Contextual Notes

There is a mention of the coefficient of static friction and the gravitational force, but the specific values and conditions under which the problem is set are not fully detailed. The discussion reflects an exploration of different equations and their applicability to the problem.

Paulbird20
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[SOLVED] Sphere: angle to begin sliding

Given a small mass on a sphere. Coef of static friction is .49 what angle would begin sliding.

I thought i would use inverse cos(.49/9.8) and i get 87 degrees but it is wrong any other equations i am missing?
 
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Suppose the mass is m. What is the normal force in terms of m, g, theta?

What is the frictional force... and what is the force that is causing the object to slide...
 
i think i figured it out i went and looked at some other equations and realized i needed to use tan instead of cos and i got the correct answer of 26.1 degrees Thank you for the tip.
 
Paulbird20 said:
i think i figured it out i went and looked at some other equations and realized i needed to use tan instead of cos and i got the correct answer of 26.1 degrees Thank you for the tip.

no prob. you're welcome.
 

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