What are the bounds for the double integral in this curved surface area problem?

[harrietstowe]

Homework Statement

Find the area of the part of the surface z^2 = 2*x*y that lies above the xy plane and is bounded by the planes x=0, x=2 and y=0, y=1.

Homework Equations

The Attempt at a Solution

z = Sqrt[2*x*y]
Sqrt[(partial z/partial x)^2 + (partial z/partial y)^2 +1] =
(Sqrt[2/(x*y)] * (x+y))/2
So Integrate over that but I can't figure out the bounds for this double integral.
Thank You

 

[kru_]

The boundary is a nice, neat box, so you would just integrate z over 0 <= x <= 2, 0 <= y <= 1.

 

[harrietstowe]

Ok I see. Thank You