What Are the Conditions for Prob(wx + y < c) ≈ Prob(wx < c) as w → ∞?

[jillna]

Given two random variables x and y, and a constant c

What conditions are needed to make:

Prob( w x + y &lt; c ) \approx Prob( w x &lt; c ), \text{ for } w \rightarrow \infty

Can anyone help? I think E(x) &lt; \infty and E(y) &lt; \infty might do. Is this right?

tks!

 

[Eynstone]

I think you need the expected value of y an order of magnitude less than E(x).

 

[brian44]

In the limit as w \rightarrow \infty I believe they are always equal. I will use the probability density functions (f(x),f(y), and f(x,y)) to give my reasoning.

P(wx &lt; c) = P(x &lt; c/w) = P(x &lt; 0) in the limit of w \rightarrow \infty
= \int_{-\infty}^{0}f(x)dx = \int_{-\infty}^{0}\int_{-\infty}^{\infty}f(x,y)dydx

To calculate the probability you have to add up the region of the density for which wx+y < c, which can be achieved by integrating for each x from y=-infinity to the line y=-wx+c:

P(wx +y &lt; c) = \int_{-\infty}^{\infty}\int_{-\infty}^{-wx+c}f(x,y)dydx

In the limit this becomes the y-axis, so we actually have in this case:
= \int_{-\infty}^{0}\int_{-\infty}^{\infty}f(x,y)dydx = \int_{-\infty}^{0}f(x)dx

and so they are equivalent.