What Are the Correct Steps to Determine the Thevenin Equivalent Circuit?

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Homework Help Overview

The discussion revolves around determining the Thevenin equivalent circuit with respect to specific terminals. Participants are exploring methods for calculating Thevenin resistance (Rth) and Thevenin voltage (Vth), while also addressing the complexities introduced by controlled sources and circuit components.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the use of short circuits to find Rth and question when this method is applicable. There are attempts to apply the node voltage method for Vth, with some participants expressing uncertainty about the inclusion of certain resistors in their calculations.

Discussion Status

The conversation is active, with participants sharing their attempts and questioning assumptions about circuit components. Some guidance has been offered regarding the inclusion of specific branches in calculations, and there is an exploration of differing interpretations of the problem setup.

Contextual Notes

Participants mention issues related to controlled sources and the potential for misleading information in textbooks. There is uncertainty about the role of certain resistors in the circuit, particularly regarding their impact on Rth calculations.

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Homework Statement


Find the Thevenin equivalent circuit with respect to terminals a, b


Homework Equations


i1+i2+i3..=0
v1+v2+v3..=0
i=v/R


The Attempt at a Solution


I set a short circuit across 72V, and calculated that Rth is 6Ω. My first question is, how come I can't always do this? I get problems where I have to calculate Rth a completely different way. How can I tell when this is acceptable to do?

Now I'm using the node voltage method to calculate Vth

So I did part of my equation, which is:
(v1-72)/5+v1/20+(v1-Vth)/8=0
(Vth-v1)/8-...
But I'm not sure what I use next
 

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orangeincup said:
My first question is, how come I can't always do this? I get problems where I have to calculate Rth a completely different way. How can I tell when this is acceptable to do?

Hm ... offhand, I don't remember this ever being an issue unless there is some kind of weird controlled source. Can you give an example of such a problem?
 
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phinds said:
Hm ... offhand, I don't remember this ever being an issue unless there is some kind of weird controlled source. Can you give an example of such a problem?

I meant ones with controlled sources, I don't know how to solve those. Also ones like this.

It works if I pretend the 10kΩ isn't part of the circuit, but I'm not sure why that is...
 

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If you pretend that the 10K is not part of the circuit, you cannot possibly get the right Rth, so I suggest your book has a wrong answer or something else is misleading you.
 
orangeincup said:
Now I'm using the node voltage method to calculate Vth

So I did part of my equation, which is:
(v1-72)/5+v1/20+(v1-Vth)/8=0
(Vth-v1)/8-...
But I'm not sure what I use next

You need to include the 12Ω branch for the Vth node equation.
 
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Here's what my book says for Rth, they calculated 12||20 +2.5, and ended up with 5kΩ
 

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Exactly. Why did this make you think they ignored the 10K resistor? They obviously did not
 
Why is it not in the equation though? It is because it's parallel to a zero resistor?
 
orangeincup said:
Why is it not in the equation though? It is because it's parallel to a zero resistor?

Reread post #4. Forget what the book says. Do it right and you'll get the right answer (which is NOT the answer they got, 'cause they didn't do it right).

Why would you think it is parallel with a zero ohm resistor? WHAT zero ohm resistor?
 

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