Writing Kirchhoff Rules for a Multi-Loop Circuit

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Homework Help Overview

The discussion revolves around writing Kirchhoff's rules for a multi-loop circuit, specifically in the context of a programming class rather than a physics class. The original poster expresses uncertainty about the correctness of their equations and the number of currents in the circuit.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to formulate Kirchhoff's voltage law (KVL) equations for the circuit but questions their validity, particularly regarding the inclusion of certain resistors and the number of currents. Some participants suggest identifying the number of meshes to determine the number of currents needed for the equations.

Discussion Status

Participants are actively engaging in refining the equations and clarifying the definitions of current directions. Some guidance has been offered regarding the number of independent loops and the need for consistent current direction in the equations. There is ongoing exploration of the correct formulation of the KVL equations.

Contextual Notes

There is mention of potential confusion regarding the definition of current directions and the arrangement of loops in the circuit. The original poster has expressed uncertainty about the completeness of their equations and the overall setup of the circuit.

carterq
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Homework Statement


I need to write Kirchhoff rues for the following circuit. This is not for a physics class, but for a programming class. I can do that part, but I am not sure if the equations are correct.

Homework Equations


upload_2017-4-25_11-6-13.png


The Attempt at a Solution


V1-I1*R1-(I1-I2)R3-I1*R2=0
V2-(I2-I3)R5-I2*R4-(I2-I1)R3=0
V3-I3*R6-I3*R7-(I3-I2)R5=0
These neglect R8, however.
Should I also include:
V1-I1*R1-(I1-I2)R3-(I1-I2)R4-(I1-I3)R7-I1*R8=0
V2-(I2-I3)R5-(I2-I3)R7-(I2-I1)R8-(I2-I1)R2-(I2-I1)R3=0
V3-I3*R6-(I1-I3)R8-(I3-I1)R2-(I3-I2)R4-(I3-I2)R5=0
These last three equations seem really wrong. I am not sure how many currents there even are.
 

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carterq said:
I am not sure how many currents there even are.
For writing KVL, take no of currents= no of meshes (smallest loops). You can see 4 meshes here, so assume four currents.

See this example.
download (1).png

You can now write the current through each resistor in terms of i1, i2 and i3. For example, current through the 25 ohm resistance is i1-i2 downward.
 
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carterq said:

Homework Statement


I need to write Kirchhoff rues for the following circuit. This is not for a physics class, but for a programming class. I can do that part, but I am not sure if the equations are correct.

The Attempt at a Solution


V1-I1*R1-(I1-I2)R3-I1*R2=0
V2-(I2-I3)R5-I2*R4-(I2-I1)R3=0
V3-I3*R6-I3*R7-(I3-I2)R5=0
These neglect R8, however.
So they are wrong. Why did you write them?
carterq said:
Should I also include:
V1-I1*R1-(I1-I2)R3-(I1-I2)R4-(I1-I3)R7-I1*R8=0
V2-(I2-I3)R5-(I2-I3)R7-(I2-I1)R8-(I2-I1)R2-(I2-I1)R3=0
V3-I3*R6-(I1-I3)R8-(I3-I1)R2-(I3-I2)R4-(I3-I2)R5=0
These last three equations seem really wrong. I am not sure how many currents there even are.

These equations are also wrong.
Choose loops and loop currents and draw the currents clearly. Note that you have 4 independent loops, so you need to write 4 loop equations.
This is a possible arrangement:

upload_2017-4-26_7-34-43.png
 
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So these are the new equations that I came up with, but something still is not quite right:
V1-I1*R1-(I1-I2)*R3-(I1-I4)*R2=0
V2-(I2-I3)*R5-(I2-I4)*R4-(I2-I1)*R3=0
V3-(I3-I2)*R5-(I3-I4)*R7-I3*R6=0
I4*R8+(I4-I1)*R2+(I4-I2)*R4+(I4-I3)*R7=0
 
In your third equation you ignored the defined current direction of I3. You did your "KVL walk" around the loop counterclockwise, which is fine, but you wrote the equations as though you were going in the direction if I3 rather than against it. For example, I3 should cause a potential rise as you pass through R5.

Once you've defined the direction of a current and used it in other equations you must stick to what you've defined.
 
Thank you! That makes sense.
 

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