What Are the Eigenvalues and Degeneracies of a Coupled Ising Spin System?

Click For Summary

Homework Help Overview

The problem involves a coupled Ising spin system described by a Hamiltonian that includes interactions between two Ising spins. The original poster seeks to determine the eigenvalues and degeneracies of this Hamiltonian, which is expressed in terms of the spins' values and coupling constants.

Discussion Character

  • Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the eigenvalues using a 2×2 matrix based on the four possible combinations of the spins. However, there is uncertainty about the correctness of this approach and the physical insight gained from it. Some participants suggest using a 4×4 matrix instead, questioning the appropriateness of the original poster's method.

Discussion Status

Participants are exploring the implications of using different matrix sizes for the Hamiltonian. There is a suggestion that a 4×4 matrix is necessary due to the number of basis states, and this perspective is being discussed without reaching a consensus on the original poster's approach.

Contextual Notes

The discussion includes considerations about the number of basis states and how the Hamiltonian should be constructed based on the configurations of the spins. There is an ongoing examination of the assumptions regarding the matrix representation of the Hamiltonian.

Krischi
Messages
2
Reaction score
0

Homework Statement

Consider two Ising spins coupled together
−βH = h(σ1 + σ2) + Kσ1σ2,
where σ1 and σ2 commute and each independently takes on the values ±1.
What are the eigenvalues of this Hamiltonian? What are the degeneracies of the states?

The Attempt at a Solution

Four possible combinations for (σ1,σ2): (1,1), (1,-1), (-1,1) and (-1,-1).
Therefore H=(-h/β)*(σ1 + σ2) + K/β*σ1σ2 can be written in a 2×2 matrix. And the eigenvalues λ are obtained by det(H-Eλ)=0.

it follows: [(-2h/β)-(K/β)-λ)][(-2h/β)-(K/β)-λ)]-(2K/β)=0

and so: λ1,2=-((2h-K)/β)±sqrt[(2h-K)22)-((2h-K)22-(2K/β)]

and: λ1,2=-((2h-K)/β)±sqrt[2k/β]

Are these really the eigenvalues of the hamiltonian? I don't gain any physical insight by this solution and therefore I doubt my calculation. I don't know how to go on and clculate the degeneracies of the states.

Thanks in advance!
Krischi
 
Physics news on Phys.org
You should use a 4x4 matrix for the Hamiltonian --- the system has 4 basis states (which you listed). Find the eigenvalues of that matrix.
 
Really, a 4[tex]\times[/tex]4 matrix? If there are 4 base states, why can't I use a 2[tex]\times[/tex]2 matrix? 4 states fit into a 2[tex]\times[/tex]2 matrix, right? I tried this and calculated 2 eigenvalues, [tex]\lambda[/tex], but I am not sure, if the result is correct, since it "looks" to complicated (see my 1st reply)
 
genneth is right, for 4 base states you need a 4x4 matrix.
Consider for a moment a Hamiltonian for a single spin that can be +1 or -1. We need to know how the Hamiltonian operator acts on the particle if its spin is +1 and also how the Hamiltonian acts on the particle if its spin is -1. Thus, we need a basis state for each state of the particle.

In your case you have two particles. So you have two particles with two states each 2*2 = 4 basis states. You need to know how the Hamiltonian acts on each individual configuration of spins and there are 4 possible configurations.

Hope that helps
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
17
Views
4K
Replies
7
Views
2K