What are the formulas for calculating current and voltage in a divider circuit?

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In the discussion on calculating current and voltage in a divider circuit, participants focused on the correct application of voltage divider principles. The voltage across two 100-ohm resistors was confirmed to be 1.25V, while the voltage Vx was recalculated to be 1.125V using the voltage divider rule for the 90-ohm and 20-ohm resistors. There was an emphasis on ensuring that potential drops do not exceed the supply voltage. Additionally, a suggestion was made to simplify calculations by multiplying the current i3 by 90Ω for efficiency. Accurate calculations are crucial for understanding circuit behavior.
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Homework Statement



Calculate ig, i0, i1, i2, Vx using current and voltage divider.

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The Attempt at a Solution



http://s13.postimg.org/77gjkkmgn/001.jpg
 
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You were doing fine until you got to the calculation of Vx. There's no way a potential drop in the the circuit can be larger than the supply voltage...
 
Yes you're right. I didn't pay attention to that.
V should be 1.25V(voltage divider on both 100 ohm resistors) and Vx = 1.125V (voltage divider between the 90 and 20//20 ohm resistors)
 
sevag00 said:
Yes you're right. I didn't pay attention to that.
V should be 1.25V(voltage divider on both 100 ohm resistors) and Vx = 1.125V (voltage divider between the 90 and 20//20 ohm resistors)

Muuuch better :smile:

You could also have just multiplied your i3 by 90Ω.
 
Yay!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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