What Are the Odds of Hitting A, J, or 2 on the Flop in Poker?

  • Context: Undergrad 
  • Thread starter Thread starter Offramp
  • Start date Start date
  • Tags Tags
    Probability
Click For Summary
SUMMARY

The probability of hitting at least one of the cards "A", "J", or "2" on the flop in a poker game with 10 or fewer players is calculated based on the remaining deck after the initial two cards are dealt. The probability of the first card being "A", "J", or "2" is 12/52 (0.230), the second card is 12/51 (0.235), and the third card is 12/50 (0.240). The total probability of hitting at least one of these cards is approximately 0.635 when considering the scenario where none of the dealt cards are "A", "J", or "2". The calculations demonstrate that the number of players does not affect the probability of the flop cards.

PREREQUISITES
  • Understanding of basic poker rules and terminology
  • Familiarity with probability concepts and calculations
  • Knowledge of combinatorial mathematics
  • Ability to analyze card distributions in a standard 52-card deck
NEXT STEPS
  • Study advanced poker probability calculations, including conditional probabilities
  • Learn about combinatorial analysis in card games
  • Explore the impact of player knowledge on poker strategy
  • Research the concept of expected value in poker scenarios
USEFUL FOR

This discussion is beneficial for poker players, statisticians, and game theorists interested in understanding the probabilities involved in card games, particularly in evaluating the likelihood of specific outcomes on the flop.

Offramp
Messages
2
Reaction score
0
What is the probability of anyone one of "A, J, 2" showing up on the the 3 card flop. I am assuming the number of player is 10 or less. I am assuming the probability is the same if it's 1 or 10 players , right? This is what I've calculated. Please let me know if I am correct.

Prob of 1st card being A, J or 2 is 12/52 = 0.230
if 1st card is none of the above then,

Prob of 2nd card being A, J or 2 is 12/51 =0.235
if 2nd card is none of the about then..

Prob of 3rd card being A, J, 2 is 12/50= 0.240

I would then sum up the prob. which is 0.705 am I correct?
 
Physics news on Phys.org


While the probability does NOT depend on how many players there are, it does depend on what information you have: in other words what cards you have been dealt before the flop.

Assuming that you were not dealt any "A", "J", or "2", then, yes, the probability the first card is "A", "J", or "2" is 12/52= 0.230 and the probability that it is NOT is 48/52.

The probability that the first card is NOT one of those and the second card IS would be 12/51 times 48/52= 0.217 (approx.). The probability, in this case, that the second card is NOT one of those would be 1-0.217= 0.783.

The probability that the first two cards are NOT one of those three but the third card is would be 12/50 times 0.783= 0.188.

The probability that exactly one of the three cards is one of "A", "J", "2" is 0.230+ 0.217+ 0.188= 0.635.

The probability that at least one of the three cards is "A", "J", "2" would be much more complicated to calculate.
 


HallsofIvy said:
Assuming that you were not dealt any "A", "J", or "2", then, yes, the probability the first card is "A", "J", or "2" is 12/52= 0.230 and the probability that it is NOT is 48/52.
I don't think that is quite right: since you've been dealt two cards, you know what two of those cards are. If you've not got one of A J 2, then the probability of A J or 2 being the first card on the flop is 12/50. (etc.. for the other cards of the flop.)
 


assuming that the two cards dealt to the players are NOT KNOWN, then what is the probability that atleast one of the 3 cards on the flop is a A, J, 2?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
33
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K