What Are the Products of These Double Replacement Reactions?

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SUMMARY

This discussion focuses on double replacement reactions in chemistry, specifically the process of predicting products from given reactants. Key steps include breaking down each compound into its ionic components, switching ions to form new compounds, and determining if a reaction occurs based on the formation of a precipitate, gas, or neutralization. An example provided is the reaction between sodium hydroxide (NaOH) and copper(II) sulfate (CuSO4), resulting in sodium sulfate (Na2SO4) and copper(II) hydroxide (Cu(OH)2), which precipitates. The discussion emphasizes the importance of balancing chemical equations after determining the products.

PREREQUISITES
  • Understanding of ionic compounds and their dissociation in water
  • Familiarity with the concepts of precipitates, gases, and neutralization reactions
  • Knowledge of balancing chemical equations
  • Basic understanding of polyprotic acids and transition metal hydrolysis
NEXT STEPS
  • Study the process of balancing chemical equations in detail
  • Learn about the solubility rules for ionic compounds
  • Explore the behavior of polyprotic acids in chemical reactions
  • Investigate the hydrolysis of transition metals and their reactions
USEFUL FOR

Chemistry students, educators, and anyone interested in mastering double replacement reactions and balancing chemical equations.

GDawg36
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^^Double Replacement Reactions^^
NaOH+CuSO4 -> ?
NH4I+AgNO3 -> ?
K2CO3+ Ba(OH)2 -> ?
KOH+ HI -> ?
K2CO3 + HNO3 -> ?
(NH4)2SO4+BaCl2 -> ?
Na2S+ NiSO4 -> ?
Pb(NO3)2+KBr -> ?
Fe2(SO4)3 +Ba(OH)2 -> ?
Hg2(NO3)2+KI -> ?
Don't really get this...Please Help!
 
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Well I'm definitely not going to do this all for you, and your text should explain this anyways. This type of stuff should be posted in the homework section...

Generally speaking for double replacement reactions:
1) Break each species into ions.
2) Switch the ions around so that new species form.
3) Reaction will occur if there is a) formation of a precipitate b) formation of a gas c) neutralization. Otherwise the reaciton will not occur.
4) Balance equation.

Your first one:
NaOH + CuSO4

NaOH --> Na+ + OH-
CuSO4 --> Cu+2 + SO4-2

Switch them up so you have Na+ and SO4-2. Therefore you need 2 Na+ for one SO4-2: Na2SO4.

And you're left with Cu+2 and OH_. You need 2 OH- for one Cu+2: Cu(OH)2

This reaction occurs because Cu(OH)2 forms a precipitate (is mostly insoluble in water).

Now balance your equation:

2NaOH (aq) + CuSO4 (aq) --> Na2SO4 (aq) + Cu(OH)2 (s)

When factoring binomials in algebra, you use FOIL method (first outside inside last). My chemistry teacher called this the "OI" method for outside inside. This might help you remember it.

Things get more complicated with polyprotic acids and hydrolysis of transition metals.

Also remember that carbonic acid is unstable so:
H2CO3 --> H2O + CO2

Other than that all of those are rather straightforward.
 

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