MHB What are the real numbers a, b, and c that satisfy certain conditions?

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To find the real numbers a, b, and c that meet the conditions a^2 + b^2 + c^2 = 26, a + b = 5, and b + c ≥ 7, the equations can be manipulated to express c in terms of a and b. Substituting b = 5 - a into the first equation leads to a quadratic in terms of a. The inequality b + c ≥ 7 can also be expressed using the derived values of b and c. Solving these equations reveals the possible values for a, b, and c that satisfy all conditions. The solution process involves algebraic manipulation and consideration of inequalities to ensure all criteria are met.
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Determine all three real numbers $a, \,b$ and $c$ which satisfies the conditions $a^2+ b^2+ c^2= 26$, $a + b = 5$ and $b + c\ge 7.$
 
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My attempt:

$a^2+b^2+c^2 = 26\;\;\;\;(1).$

$a+b = 5\;\;\;\;(2).$

$b+c \ge 7\;\;\;\;(3).$

Combining $(1)$ and $(2)$:

\[a^2+b^2+c^2 = (5-b)^2+b^2+c^2 = 26\Rightarrow 2b^2-10b+c^2-1 = 0, \;\;\;\;(4).\]

From $(3)$ one gets: \[c^2 \geq (7-b)^2, \;\;\;\; (5).\]

Combining $(4)$ and $(5)$:

\[2b^2-10b+c^2-1 = 0 \geq 2b^2-10b+(7-b)^2-1 = 3b^2-24b+48\]

\[\Rightarrow b^2-8b+16 \leq 0\]

Or \[(b-4)^2 \leq 0\]

So the only possible $b$-value is $4$. Thus $a = 1$ (from $(2)$) and $c = 3$ (from $(1)$ and $(3)$).
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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