What Are the SI Units of the Gravitational Constant in Newton's Law?

  • Thread starter Thread starter RCAF91
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on determining the SI units of the gravitational constant (G) in Newton's Law of Universal Gravitation. The equation Fg = G(M1)(M2) / D^2 requires that the units of G be such that the overall units equal Newtons (N). Through dimensional analysis, it is established that the units of G must be m^3 kg^-1 s^-2 to maintain dimensional consistency in the equation.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with dimensional analysis
  • Knowledge of SI units (meters, kilograms, seconds)
  • Basic physics concepts related to force and mass
NEXT STEPS
  • Study the derivation of SI units in physics
  • Learn about dimensional analysis techniques
  • Explore the implications of gravitational force in astrophysics
  • Investigate the role of constants in physical equations
USEFUL FOR

Students of physics, educators teaching gravitational concepts, and anyone interested in the foundational principles of force and mass in the context of universal gravitation.

RCAF91
Messages
5
Reaction score
0
Newton's Law of Universal Gravitation states that the magnitude of the force of gravity (Fg) between any two objects in the universe depends on the mass of each object (M1 and M2) as well as the distance (D) between them. The equation to describe this functional relationship is given by:

Fg = G(M1)(M2) / D^2

where G is a constant called the "constant of universal gravitation"

Use dimensional analysis to determine what SI units the constant of universal gravitation must carry for Newton's equation to be dimensionally valid.


In the case of this question, would anyone be able to show me what they are looking for? Much appreciated!
 
Physics news on Phys.org
Welcome to physics forums.

The problem is asking you for the units of G. What do the units of G need to be so that the units of G\frac{M_1M_2}{D^2} are Newtons? (because the SI unit of force is the Newton)
 
Nathanael said:
Welcome to physics forums.

The problem is asking you for the units of G. What do the units of G need to be so that the units of G\frac{M_1M_2}{D^2} are Newtons? (because the SI unit of force is the Newton)

Would you mind explaining the steps on how to reach the answer? I'm still a bit unsure how you determine this given the variables.
 
M is mass. What are the units of mass? Can you take it from there?
 
Figured it out, thanks.
 

Similar threads

Replies
2
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 20 ·
Replies
20
Views
2K
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
2
Views
4K