Ali Asadullah
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We know that the solutions of x^y=y^x are (2,4) and (4,2), but please tell me how to solve it. I have tried to take log wrt x on both side.
The equation x^y = y^x has established solutions including (2,4), (4,2), (3,3), and (4.4). Additional solutions exist for the form (3,y) where y can equal 3 or approximately 2.478. The discussion highlights the possibility of complex solutions and emphasizes the need for logarithmic manipulation to explore these relationships further. For a comprehensive understanding, refer to the linked Physics Forums thread.
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Ali Asadullah said:We know that the solutions of x^y=y^x are (2,4) and (4,2)