What are the steps for solving a 2nd order differential equation?

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Firstly, suppose y1 is a solution to y''+ay'+by=g(x). What then is a solution of y''+ay'+by=kg(x), where k is an arbitrary non-zero constant?

Secondly, note that a general solution to a non-homogenous linear ODE is its homogenous solution plus one particular solution to its nonhomogenous ODE.
 
solution to y''+ay'+by=kg(x) is ky1?

so the solution to y''+ay'+by=3g(x) is the complimentyery function + particular integral = 3y1 + y2?
 
thanks!
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