- #1

Pushoam

- 962

- 52

## Homework Statement

## Homework Equations

## The Attempt at a Solution

For the homogeneous equation, I have got the the root of the characteristic equation as ## e^{ix}, e^{-ix} ## .

So, the corresponding solution is ## B \sin{ x} + A \cos{ x} ## .

Then, I took the particular solution as C.

Putting C in the differential equation , I get C = -1.

So, the inhomogeneous solution is ## A \cos{ x} + B \sin{ x} – 1 ## , i.e. option(e).

Is this correct?