What are the three solutions to x^3 = -0.5?

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what is (-1)1/2
 
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actually i missed the point , i wanted to ask that is the positive fractional power of a negative number possible , like (-0.5)^1/3
 


phymatter said:
actually i missed the point , i wanted to ask that is the positive fractional power of a negative number possible , like (-0.5)^1/3

The point is that there are two answers to your first question and three to your second.
 


ONE of the three numbers, x, such that [itex]x^3= -0.5[/itex], is a real number (it is approximately -0.7937), the other are two complex numbers, 0.3968+ 0.6874i and 0.3969- 0.6974i, approximately (and assuming I have done the arithmetic correctly).

In the real number system we can distinguish between two square roots in that one is positive and the other negative. And we define [itex]a^{1/2}[/itex] to be the positive number, x, such that [itex]x^2= a[/itex]. The complex numbers, however, cannot be made into an ordered field so there is no way of distinguishing one of the two square roots.
 
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