What are the values of m and n on the line L1?

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The line L1 passes through the point (4,3,-2) and is parallel to the line defined by the parametric equations (x=1+3t, y=2-4t, z=3-t). To find the values of m and n for the point (m,n,-5) on L1, one must establish the direction vector of the parallel line, which is (3,-4,-1). By applying the parametric equations of L1, the values of m and n are determined to be 13 and 14, respectively. This conclusion was confirmed by members MarkFL, anemone, and Sudharaka.

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The line $L_1$ goes through the point $(4,3,-2)$ and is parallel to the line defined by $(x=1+3t, y=2-4t, z= 3-t)$. If the point $(m,n,-5)$ is also on $L_1$ then find the values of $m$ and $n$.
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Congratulations to the following members for their correct solutions:

1) MarkFL
2) anemone
3) Sudharaka

Solution (from Sudharaka):
The line \(L_1\) should go through the point \((4,\,3,\,-2)\) and should be parallel to the vector \((3,\,-4,\,-1)\). The equation of the line \(L_1\) in vector form can be written as,

\[L_1:\, (x,\,y,\,z)=(4,\,3,\,-2)+t(3,\,-4,\,-1)\]

Since \((m,\,n,\,-5)\) is on \(L_1\) we have,

\[L_1:\, (m,\,n,\,-5)=(4,\,3,\,-2)+t(3,\,-4,\,-1)\]

\[\Rightarrow t=3\]

\[\therefore m=4+3t=13\mbox{ and }n=3-4t=-9\]
 

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