What are the values of s that make two given vectors orthogonal?

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SUMMARY

The discussion centers on determining the scalar values of s that make the vectors b = X + sY and c = X - sY orthogonal by evaluating their dot product. The key equation derived is (X + sY) · (X - sY) = 0, leading to the conclusion that 1 - s² = 0. This results in two solutions for s: s = 1 and s = -1. The user also seeks confirmation of their calculations and understanding of the geometric representation of orthogonal vectors.

PREREQUISITES
  • Understanding of vector operations, specifically dot products.
  • Familiarity with the concept of orthogonality in vector spaces.
  • Basic knowledge of unit vectors and their properties.
  • Ability to interpret geometric representations of vectors.
NEXT STEPS
  • Study vector dot product properties in detail.
  • Explore the geometric interpretation of orthogonal vectors.
  • Learn about vector spaces and their dimensional properties.
  • Investigate applications of orthogonal vectors in physics and engineering.
USEFUL FOR

Students of linear algebra, mathematicians, and anyone interested in vector calculus or physics applications involving orthogonal vectors.

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By evaluating the dot product,

find the values of the scalar s for which the two vectors
b=X+sY and c=X-sY
are orthogonal
also explain your answers with a sketch:





my working

(X,sY).(X,-sY) has to equal 0 for them to be orthogonal

x.x = 1 since they are unit vectors
sY.-sY = -1 to make the whole thing 0

s = 1
1*y . -1*y = -1

1-1 =0

sketch would be two vectors perpendicular to one another?
 
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could someone please inform me If my work is correct?
cheers
 
(X + sY).(X - sY) = 0
==> X.X + sY.X - sX.Y -s2Y.Y = X.X - s2Y.Y = 0
==> 1 - s2 = 0

You found one solution for s; there are two.
 

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