What causes confusion in testing time invariance?

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SUMMARY

The discussion centers on the concept of time invariance in systems, specifically analyzing the function $$y(t)=x(\alpha t-\beta)$$. The confusion arises when testing time invariance by shifting the input $$x(t)$$ to $$x_1(t_1)=x(t-t_o)$$ and substituting it into the output, resulting in $$x(\alpha t-t_o-\beta)$$ instead of the expected $$y(t)=x_1(\alpha t_1 - \beta)$$. This indicates a potential misunderstanding of the underlying mathematical principles governing time invariance, suggesting that $$y(t)$$ may not be time invariant under certain transformations.

PREREQUISITES
  • Understanding of time invariance in systems theory
  • Familiarity with mathematical transformations and function manipulation
  • Knowledge of the properties of linear systems
  • Basic proficiency in calculus and differential equations
NEXT STEPS
  • Study the mathematical foundations of time invariance in linear systems
  • Explore the implications of shifting inputs and outputs in system analysis
  • Review examples of time-invariant and time-variant systems in control theory
  • Investigate the role of parameters like $$\alpha$$ and $$\beta$$ in system behavior
USEFUL FOR

Students and professionals in engineering, particularly those studying control systems, signal processing, or systems theory, will benefit from this discussion on time invariance and its mathematical implications.

Bullington
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I understand what time invariance means but there are a few catches that I'm completely confused about: Suppose we have $$y(t)=x(\alpha t-\beta)$$ to test time invariance we shift the input then "plug" it into the output:$$x_1(t_1)=x(t-t_o)$$ so this is when I become confused; when we plug $$x_1(t_1)$$ into $$y(t)$$ we get: $$x(\alpha t-t_o-\beta)$$ instead of $$y(t)=x_1(\alpha t_1 - \beta)=x(\alpha (t-t_o) -\beta)$$ I believe there is some underling math I am unaware of; but, what is it? Any sources?
 
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