MHB What Comparison Sign To Assert f^(-1)(f(A))? A True?

  • Thread starter Thread starter ranga519
  • Start date Start date
  • Tags Tags
    Functions
Click For Summary
For a function f from set X to set Y and subset A of X, the relationship f^(-1)(f(A)) can be compared to A using the subset relation. It is established that A is always a subset of f^(-1)(f(A)), meaning A ⊆ f^(-1)(f(A)). However, equality (A = f^(-1)(f(A))) is not guaranteed, as there may exist elements outside A that map to the same output in f(A). An example is provided with constant functions, where f^(-1)(f(A)) equals X regardless of A. Thus, the comparison sign can be either ⊆ or =, depending on the nature of the function.
ranga519
Messages
4
Reaction score
0
Let f be a function from a set X to a set Y, moreover, A ⊆ X. What comparison sign canput instead? to assert "f ^(−1) (f(A)) ? A" become true? (Possible signs of comparison in this : ⊆, ⊇, =. It is necessary to take into account all options.

f ^(−1) - inverse of fall options.), Let f be a function from a set X to a set Y, moreover, A ⊆ X. What comparison sign canput instead? to asserte-one(f (a))?become true? (Possible signs of comparison in this and the following two problems: ⊆, ⊇, =. It is necessary to take into accountall options.)
 
Physics news on Phys.org
ranga519 said:
Let f be a function from a set X to a set Y, moreover, A ⊆ X. What comparison sign canput instead? to assert "f ^(−1) (f(A)) ? A" become true? (Possible signs of comparison in this : ⊆, ⊇, =. It is necessary to take into account all options.


Suppose $x\in A$. Then $f(x)\in f(A)$ so that $x\in f^{-1}(f(A))$. But there might exist $y\notin A$ such that $f(y)\in f(A)$. That y would also be in $f^{-1}(f(A))$. So what we can say is that $A\subseteq f^{-1}(f(A))$ with the "=" possible but not necessarily. For example if f is a "constant function", $f(x)= y\in Y$ for all $x\in X$ where y is a specific member of Y, then $f^{-1}(f(A))= X$ for A any subset of X.
 
There is a nice little variation of the problem. The host says, after you have chosen the door, that you can change your guess, but to sweeten the deal, he says you can choose the two other doors, if you wish. This proposition is a no brainer, however before you are quick enough to accept it, the host opens one of the two doors and it is empty. In this version you really want to change your pick, but at the same time ask yourself is the host impartial and does that change anything. The host...

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
Replies
7
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
7K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K