What Determines the Current in an AC Circuit with a Light Bulb?

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SUMMARY

The discussion centers on determining the current in an AC circuit with a light bulb when subjected to a sinusoidal voltage of V = 763 sin(2π(22)t) V. The correct answer for the initial current when the voltage is first applied is 0 A, as the instantaneous voltage at t=0 is also 0. For t = T/4, the current can be calculated using the relationship P = I * V, but the average power of 17 W must be used in conjunction with the RMS values, leading to the conclusion that the instantaneous power cannot be directly equated to average power.

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The current in the circuit ...??

Homework Statement



An AC voltage of the form V = Vmax sin 2*pi*f*t , with frequency 22 Hz and maximum voltage 763 V, is applied across a 17 W light bulb. When the voltage is first applied.

a) what is the current through the circuit?

Three Choices :

1. the maximum current
2. 0
3. the rms current

What is the correct answer and why ... ??


b) When t = T/4 , where T is the period of the applied voltage, what is the current in the circuit?



Homework Equations



P = I * V
I max = \sqrt{}2 * I rms
T = 1/f


The Attempt at a Solution



In part a) i think that when the voltage is first applied means that time is ZERO so it could be ZERO the options # 2

In part b) I substituted t = 0.25T or 0.25/f in this formual

V = Vmax sin 2*pi*f*t

I found V then I used P = I * V and solved for I but i got wrong answer.
 
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17 W is the average power over a full cycle. It's equal to I_{rms} V_{rms}. You used this value as if it was the instantaneous power at t=0.25T
 

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